3 years ago

Factor the quadratic expression completely 6x^2 – 28x + 32

Mathematics

1 answer:

Fiesta28 [93]3 years ago

7 0

Answer: 2(x-2)(3x-8)

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Please help fast ^^

allsm [11]

The discriminante :
b^2-4ac

1^2 - 4 * -2 * -28 = 1 - 224 = -223

When the discriminant (b^2-4ac) is less than 0, the equation had no real solutions.

-223<0, so, 2x^2+x-28 = 0 has no real solutions.

Hope that helps :)

7 0

2 years ago

Use the given endpoint R and the midpoint M of segment RS to find the coordinates of the other endpoint S. (Hint: Use the midpoi

zimovet [89]

Using the given endpoint R (8,0)and the midpoint M (4,-5) , the other endpoint S is (0,-10)

Explanation :

Use the given endpoint R and the midpoint M of segment RS

R (8, 0 ) and M (4, -5 )

Let 'S' be (x2,y2)

Apply the midpoint formula

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\$

Endpoint R is (x1,y1) that is (8,0)

Substitute the values and make it equal to M(4,-5)

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\\\(\frac{8+x_2}{2},\frac{0+y_2}{2} )=(4,-5)\\\\\frac{8+x_2}{2}=4\\8+x_2=8\\x_2=8-8=0\\x_2=0\\\\\\\frac{0+y_2}{2} =-5\\y_2=-10$