Answer:
$0.30
Step-by-step explanation:
If you already spent $5 then you have $6 remaining so you will just divide 6 and 20 and you will get 0.3 so $0.30
Answer:
The highest altitude that the object reaches is 576 feet.
Step-by-step explanation:
The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be
, the first and second derivatives are, respectively:
First Derivative

Second Derivative

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:


(Critical value)
The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:


The highest altitude that the object reaches is 576 feet.
Answer:
anything but 2
Step-by-step explanation:
f(-1/2)
If you plug in 2, you'd get -1. But if you plug in other values, it won't be equal to -1.
Answer:
99% Confidence interval: (1196,1973)
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 20
Mean, μ = 1584
Standard Deviation, σ = 607
99% Confidence interval:
Putting the values, we get,

Thus, there is a 99% chance that it will break in approximately 1196 to 1972
Answer:
- h(t) = -16t^2 +188
- 3.4 seconds
Step-by-step explanation:
The usual equation for ballistic motion is ...
h(t) = -16t^2 +v0·t +s0
where v0 is the initial upward velocity, and s0 is the initial height above some reference point.
Here, we presume there is no initial vertical velocity, and the height is given as 188 ft above the river. Since we want the time to reach the river, we're solving ...
h(t) = -16t^2 +188
h(t) = 0
-16t^2 +188 = 0
t^2 -11.75 = 0
t = √11.75 ≈ 3.4
It takes about 3.4 seconds for the log to reach the river.