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Korvikt [17]
2 years ago
15

Six stand up comics (A, B, C, D,E & F) are to preform one night at a comedy club. What is the probability the comic C will p

reform first, comic E will perform second and either comic A or B will perform third?
A.)(1/6)•(1/6)•(2/6)
B.)(1/6)+(1/5)+(2/4)
C.)(1/6)•(1/6)•(1/3)
D.)(1/6)•(1/5)•(1/2)
Mathematics
1 answer:
vaieri [72.5K]2 years ago
4 0

Answer:

B

Step-by-step explanation:

There are 6 comedies and 2 people who will try going 2 times and there is a 2/6 chance for the other 2 comedians

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