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beks73 [17]
3 years ago
11

How are the solution sets to s<3 and |s|<3 different ?

Mathematics
1 answer:
Contact [7]3 years ago
8 0

Answer:

they are different because of the mode sign on the second 's',

which if you are wondering what it stands for,

it represents only the magnitude of the value needed, not its sign,

let the assumed value of s be -5,

for example iin the first case, s < 3

hence s = -5, and it is true for s < 3

OR

if we take the second case, lsl < 3

that would be s = 5 [ not -5], which would not be true for lsl < 3

i hope u understood it,

if any more questions...please ask :)

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A rectangle has an area of 16 cm2 do you know its length <br><br> HELP
Helga [31]

Answer:

This answer is based on that I don't know what that 2 is for

Step-by-step explanation:

There are many different answers for this question

Area is l times w so 4 times 4 = 16 the lengths could be 4

If one of the sides is 2 then the length must be 8 because 8 times 2 is 16

7 0
3 years ago
Find the value of L in the equation. <br> s=(n÷2)(a+L)
Anon25 [30]

Answer:

2s/n-a=L

Step-by-step explanation:

So first we divide (n÷2) so it will be s/(n÷2) =a+L. Next we subtract L and get s/(n÷2)-a. That's not it yet, since 2 is being divided in the denominator, we have to reciprocal it meaning multiply, it to the top value. So it would 2s/n-a=L. But you can just leave it like that if you desire and your teacher doesn't mind.

7 0
3 years ago
Which two values of x are roots of the polynomial below?<br> 5x2 - 5x+1
Natalija [7]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

5 {x}^{2}  - 5x + 1 = 0

(x -  \frac{5 +  \sqrt{5} }{10} )(x -  \frac{5 -  \sqrt{5} }{10} ) = 0 \\

Thus :

x =  \frac{5 + \sqrt{5} }{10}  \\

x =  \frac{5 -  \sqrt{5} }{10}  \\

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6 0
3 years ago
Consider the following figure.
kirill [66]

Answer:

80 units.

Step-by-step explanation:

The rectangle ABCD is drawn and attached in the image below. The diagonal BD measures 100 units, the side BC measures 60 units.  We need to find the measure of side DC which is represented by x in the figure.

Note that a Right Angled Triangle DCB is being formed with BD as the hypotenuse and sides BC and DC as its two legs. The Pythagoras Theorem relates the length of hypotenuse and the two legs of the Right Angled Triangle as:

c^{2}=a^{2}+b^{2}

c is the length of hypotenuse = 100

a is the length of one leg = 60

b is the length of second leg = x

Using these values, we get:

100^{2}=60^{2}+x^{2}\\\\ x^{2}=100^{2}-60^{2}\\\\ x^{2}=6400\\\\ x = 80

Therefore, measure of the side DC is 80 units

7 0
3 years ago
I really need these answered!
Akimi4 [234]

Answer:

Step-by-step explanation:

#1) \arcsin \left(0.64958\right)=0.70703\dots \quad \begin{pmatrix}\mathrm{Degrees:}&40.51^{\circ \:}\end{pmatrix}

∡C =62.49

\frac{\left(\sin \left(27^{\circ \:}\right)\right)}{3}=\frac{\sin \left(54^{\circ \:}\right)}{x}\quad :\quad x=\frac{3\left(\sqrt{5}+1\right)}{\sin \left(27^{\circ \:}\right)\cdot \:4}\quad \left(\mathrm{Decimal}:\quad x=5.34603\dots \right)

6 0
3 years ago
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