three-fourths minus x = one half
so x equals one-fourth
it will be like this
3 1
-- - x = --
4 2
and i think you gonna have to do keep,change,flip so bascially flip 1/2 then after you multiple and that's how it equaals 1 one-fourth
hope this helps!
Answer:
ΔRES ≅ ΔTEQ
Step-by-step explanation:
A parallelogram is a quadrilateral (has four sides and four angles) in which opposite sides are equal and parallel to each other.
Opposite angles of a parallelogram are equal and the diagonals bisect each other. Each diagonal of a parallelogram separates it into two congruent triangles.
Given parallelogram QRST with diagonals QS and RT intersecting at point E
Therefore, the diagonals divide parallelogram QRST into congruent triangles, hence:
ΔRES ≅ ΔTEQ
There are 431 females
785-77=708
708/2=354
354=males
354+77=431
431=females
to check work do 431=354 and that equals 785
Answer:
Original Number = let we assume it is x
Number after decremented = y = 60
Total decrease = z = x-y = x-60
% of decrease = ((x-60)/x)*100 = 7.3
(x-60)*100 = 7.3x
100x -6000 = 7.3x
100x-7.3x = 6000
92.7x = 6000
x = 6000/92.7 = 64.73
Original Number = 64.73
Step-by-step explanation:
Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.
<u>Solution:</u>
Given that,
Total circulation of local newspaper in 2000 = 3250
Total circulation of local newspaper in 2001 = 3640
Total circulation of local newspaper in 2002 = 4100
<em><u>Finding percent of increase in the newspaper’s circulation from 2000 to 2001:</u></em>


<em><u>Finding percent of increase in the newspaper’s circulation from 2001 to 2002:</u></em>

As we can see 12% < 12.6%
So period of 2001 to 2002 has higher increase percentage.