9.75 x 7.2 = 70.2
Swimming Pool Area: 70.2
The Park Area: 70.2 x 1.5 = 105.3
Total Area of both Swimming Pool & Park area: 70.2 + 105.3 = 175.5
Final Answer: 175.5
By comparing the given shape with easier ones like triangles and rectangles we will see that the area of the shape is 8 square units.
<h3>
How to simplify the shape.</h3>
So the given shape is a little bit complex, but you can actually see that it is a triangle with a base of 8 units with a height of 4 units, where a rectangle of 2 in by 3 in was removed, and also removed a triangle of height of 2 inches and base of 2 inches.
Remember that:
- A triangle of height H and base B has an area = B*H/2
- A rectangle of length L and width W has an area = L*W.
Then the area of the given shape is:
A = 8*4/2 - 3*2 - 2*2/2
A = 16 - 6 - 2
A = 8
So the given shape has an area of 8 square units.
If you want to learn more about areas, you can read:
brainly.com/question/14137384
The value of the real life expression is, simple interest = $12.5
<h3>How to simplify this real life expression and show unit analysis?</h3>
The real life expression is given as:
simple interest = ($100) (0.05/year) (2.5 years
Divide 1 year by 1 year
simple interest = ($100) (0.05) (2.5)
Rewrite the equation as a product of factors
simple interest = ($100) * (0.05)* (2.5)
Evaluate the product of 0.05 and 2.5
simple interest = ($100) * 0.125
Evaluate the product of $100 and 0.125
simple interest = $12.5
Hence, the value of the real life expression is, simple interest = $12.5
Read more about expressions at:
brainly.com/question/723406
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Perpendicular lines have negative reciprocal slopes. So if the slope is -2/5...to find the negative reciprocal, " flip " the slope and change the sign.
So we flip -2/5 and we get 5/-2...and now we change the sign...and we get 5/2. So our perpendicular slope will be 5/2.
The answer is letter B. The image shows a relection because it is just the same as the original. Reflection is a transformation that gets the 2nd image just the same as the original. The transformation of DEFG is just the same as D'E'F'G'.
