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Lana71 [14]
3 years ago
5

Find the angle of elevation of the sun when a 7.6-meter flagpole casts an 18.2-meter shadow. Round to the

Mathematics
1 answer:
Gnoma [55]3 years ago
7 0

Answer:22.7

Step-by-step explanation:

Okay so the situation given shows a right triangle with the two sides being 7.6 and 18.2. So we can find the angle of elevation using tangent, which is tan-1*7.6/18.2. I got 22.66 so 22.7

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Which athletes, if any, would qualify for the finals if the length of a jump that qualifies for the finals were at least 20 feet
saul85 [17]

Answer:

Amir and ryan would qualifiey

Step-by-step explanation:

5 0
2 years ago
Solve by graphing. Y = 1/3x - 3, Y= -x + 1<br><br> How do you solve this?
givi [52]

Step-by-step explanation:

Y=1/3-3/1

-x+1= 1/3-3/1

= -3+1

= -2.

3 0
2 years ago
Which describes how to find the solution to 3p &lt; 14?
Sever21 [200]

Answer:

A. divide both sides by 3

Step-by-step explanation:

3p < 14

We want to isolate p, so we divide both sides by 3

3p/3 < 14/3

p <14/3

7 0
3 years ago
Solve the system of equations using multiplication. 3x – 3y = –3 5x – y = –13 What is the solution of the system?
love history [14]

ANSWER

The solution is

x=-3,y=-2

EXPLANATION

First equation

3x – 3y = –3

Second Equation:

5x – y = –13

Multiply the second equation by 3 to get:

Third equation:

15x-3y=-39

Subtract the first equation from the third equation:

15x - 3x =  - 39 -  - 3

12x =  - 36

Divide both sides by 12,

x =  \frac{ - 36}{12}  =  - 3

Put x=-3 into the first equation:

3( - 3) - 3y =  - 3

- 9  - 3y =  - 3

Group like terms,

- 3y =  - 3 + 9

- 3y = 6

y =  - 2

The solution is

x=-3,y=-2

6 0
3 years ago
PIUWawilities
blondinia [14]

Answer:

23.44%

Step-by-step explanation:

The probability of getting a 4 on the first 2 throws and different numbers on the last 5 throws = 1/6 * 1/6 * (5/6)^5

= 0.01116

There are 7C2 ways of the  2 4's  being in different positions

= 7*6 / 2 = 21 ways.

So the required probability =  0.01116 * 21

= 0.2344 or 23.44%.

3 0
3 years ago
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