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Vera_Pavlovna [14]
3 years ago
6

What is the greatest common factor of 32, 44, and 48?

Mathematics
2 answers:
LekaFEV [45]3 years ago
5 0

Answer:

4

Step-by-step explanation:

Vlad1618 [11]3 years ago
4 0

Answer:

     4

Step-by-step explanation:

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the first four terms in an arithmetic sequence are $x y$, $x - y$, $xy$, and $x/y$, in that order. what is the fifth term?
olga2289 [7]

When the first four terms in an arithmetic sequence are x+y, x-y, xy and x÷y, then the fifth term will be \frac{123}{40}

A sequence of numbers in which every term (except the first term) is obtained by adding a constant number to the previous term is called an arithmetic sequence

In given arithmetic sequence

The first term = x+y

The second term = x-y

Then, the common difference= (x-y)-(x+y)

x-y-x-y= -2y

The third term = x-y+(-2y)

x-y-2y= x-3y

In question third term is given as xy

So both are equal

x-3y=xy

-3y=xy-x

-3y=x(y-1)

x= \frac{-3y}{y-1}

Similarly fourth term will be

x-3y-2y=x-5y

x-5y=\frac{x}{y}

substitute the value of x  in the equation

\frac{-3y}{y-1}-5y=\frac{\frac{-3y}{y-1} }{y} \\\frac{-3y}{y-1} -5y=\frac{-3}{y-1}\\ -3y-5y(y-1)=-3\\-3y-5y^{2}+5y=-3\\ -5y^{2} +2y+3=0\\5y^{2} -2y-3=0

Split the middle term and factorize it

5y^{2}+3y-5y-3=0\\y(5y+3)-1(5y+3)=0\\

(y-1)(5y+3)=0

y=1,\frac{-3}{5}

y cannot be equal to 1, because the third term and fourth term will become x.

y=\frac{-3}{5}

substitute the value of y in the equation of x
x=\frac{-3y}{y-1} \\=\frac{-3\frac{-3}{5} }{\frac{-3}{5}-1 }\\ =\frac{-9}{8}

The fifth term= \frac{x}{y}+(-2y)=\frac{x}{y} -2y

\frac{\frac{-9}{8} }{\frac{-3}{5} }-2\frac{-3}{5}  =\frac{123}{40}

Hence, when the first four terms in an arithmetic sequence are x+y, x-y, xy and x÷y, then the fifth term will be \frac{123}{40}

Learn more about Arithmetic sequence here

brainly.com/question/15412619

#SPJ4

5 0
2 years ago
Solve. 2x - 1 = 7<br><br> A) x=2<br> B) x=3<br> C) x=4<br> D) x=5
irinina [24]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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(x,-4) and (2,8); m=_3
DerKrebs [107]

\bf (\stackrel{x_1}{x}~,~\stackrel{y_1}{-4})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{8}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{8-(-4)}{2-x}=\stackrel{\stackrel{m}{\downarrow }}{-3}\implies \cfrac{8+4}{2-x}=-3 \\\\\\ \cfrac{12}{2-x}=-3\implies 12=(2-x)(-3)\implies 12=-6+3x \\\\\\ 18=3x\implies \cfrac{18}{3}=x\implies 6=x

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3 years ago
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