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4 years ago

6x^2 - 19x + 10 Factor

Mathematics

1 answer:

3241004551 [841]4 years ago

5 0

Answer:

(2x-5)(3x-2)

Step-by-step explanation:

1)When factoring quadratic equations in for ax²+bx+c you need to separate the b term in a way that the two addends you separate it by should equal a•c. Just do trial and error. In this case you should get -4 and -15. Your separated equation should be:

6x²-4x-15x+10

2)now factor out a common factor from the first two terms and one from the last two terms you should have:

2x(3x-2)-5(3x-2)

3)finally rewrite this equation into two separate factors and you have your answer.

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Jimmy’s Delicatessen sells large tins of Tom Tucker’s Toffee. The deli uses a periodic review system, checking inventory levels

Yakvenalex [24]

Answer:

The restocking level is 113 tins.

Step-by-step explanation:

Let the random variable X represents the restocking level.

The average demand during the reorder period and order lead time (13 days) is, μ = 91 tins.

The standard deviation of demand during this same 13- day period is, σ = 17 tins.

The service level that is desired is, 90%.

Compute the z-value for 90% desired service level as follows:

$z_{\alpha}=z_{0.10}=1.282$

*Use a z-table for the value.

The expression representing the restocking level is:

$X=\mu +z \sigma$

Compute the restocking level for a 90% desired service level as follows:

$X=\mu +z \sigma$

$=91+(1.282\times 17)\\=91+21.794\\=112.794\\\approx 113$

Thus, the restocking level is 113 tins.

6 0

4 years ago

Um please help look at the questions and answer

notsponge [240]

Answer:

ph scale

Step-by-step explanation:

because I have to test the acid for my pool

8 0

3 years ago

12) Add the fractions, and simplify if possible. (y+7)/(y^2-y-12) - 2/(y^2-9)

lianna [129]

Answer:

$\dfrac{y^2+2y-13}{(y-4)(y+3)(y-3)}$

Step-by-step explanation:

Given the expression

$\dfrac{y+7}{y^2-y-12}-\dfrac{2}{y^2-9}$

First, factor each denominator:

1. $y^2-y-12=y^2-4y+3y-12=y(y-4)+3(y-4)=(y-4)(y+3)$

2. $y^2-9=(y-3)(y+3)$

Now the expression is

$\dfrac{y+7}{(y-4)(y+3)}-\dfrac{2}{(y-3)(y+3)}$

Now, multiply the first numerator by (y-3) and the second by (y-4) and write the result as a fraction with denominator $(y-4)(y+3)(y-3):$

$\dfrac{(y+7)(y-3)-2(y-4)}{(y-4)(y+3)(y-3)}=\dfrac{y^2-3y+7y-21-2y+8}{(y-4)(y+3)(y-3)}=\dfrac{y^2+2y-13}{(y-4)(y+3)(y-3)}$

This fraction cannot be simplified more.

3 0

3 years ago

How do you determine the y-intercept and the x-intercept in an algebraic equation? I'm trying to figure out how to tell which is

natka813 [3]

If you want to find the x-intercept, you replace y in the equation with 0 and solve the equation for x.
If you want to find the y-intercept, you replace x in the equation with 0 and solve the equation for y.

Example:
$y=2x+5\\\\
\hbox{x-intercept}\\
0=2x+5\\
2x=-5\\
x=-2.5\\
\hbox{x-intercept is } (-2.5,0)\\\\
\hbox{y-intercept}\\
y=2\cdot0+5\\
y=5\\
\hbox{y-intercept is }(0,5)$

4 0

3 years ago

PLS HELP heres my question i pinned as a picture

Murrr4er [49]

Advanced ($10): A

Door ($13): D

Money: 10A + 13D = 544 ⇒ 1(10A + 13D = 544) ⇒ 10A + 13D = 544

Quantity: A + D = 46 ⇒ -10(A + D = 46) ⇒ -10A - 10D = -460

3D = 84

D = 28

Quantity: A + D = 46 ⇒ A + (28) = 46 ⇒ A = 18

Answer: advanced = 18 people, at the door = 28 people

7 0

3 years ago