1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
a^{2}=b ^{2}+c ^{2}-2bc(cosA)
2.
20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA) 400=81+169-234(cosA) 150=-234(cosA) cosA=150/-234= -0.641
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
Answer:
can i have my brainliest i helped u on the other questions pls dude
Step-by-step explanation:
Answer:
slope of line pass throught jk is 0.5 slope
since line perpendicular to jk then x × 0.5= -1 so slope of line perpendicular is -2
then eq of line is y= -2x -15
Answer:
f= 0.30, 0.50, 0.70, 0.90
Step-by-step explanation:
The distance of Erika from kite directly is 35.71 yards
Step-by-step explanation:
Considering the given situation as a right triangle with string as hypotenuse and the distance between both girls as base
So,
As the triangle is a right triangle, we can use pythagoras theorem to solve this problem.
Rounding off to nearest hundredth
=> 35.71 yards
Hence,
The distance of Erika from kite directly is 35.71 yards
Keywords: Triangle, Pythagoras
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