y = -3(x<span> - 2)^2 + 1 </span>x<span>-coordinate of vertex: </span>x<span> = -b/(2a) = -12/-6 = 2 y-coordintae of vertex: y(2) = -12 + 24 - 11 = 1 </span>Vertex form: y = -3(x<span> - 2)^2 + 1 Check. Develop y to get back to standard form: y = -3(</span>x^2 - 4x + 4) + 1 = -3x<span>^2 + </span>12x<span> - </span>11<span>. </span>
Answer:
y=-7
Step-by-step explanation:
first, you want variables on one side, numbers on the other side of the equation.
4y+4=2y-10
*plus ten on both side to get rid of -10*
4y+14=2y
*minus 4y on each side to get rid of 4y*
14=-2y
*divide by -2 on each side to get the value of just one y itself*
y=-7
Answer:
hypergeometric
Step-by-step explanation:
Meeting ID: 849 7736 5835
Passcode: DVM21S
Answer:
0
Step-by-step explanation:
Use the hint lol
Step 1: Plug in -2 into the equation.
f(-2) = 4(-2) + 8
Step 2: Multiply
f(-2) = -8 + 8
Step 3: Add
f(-2) = 0
23/8 hope it helps,,....................
