Answer:
(a) 5/7 chance
(b) 2/7 chance
(c) 5/7 chance
Step-by-step explanation:
Event X: There are 3 letters that come before "D". A, B, and C. There is a 3 out of 7 chance of picking one of those letters. (3/7)
Event Y: There are 4 letters in "C A G E". Those 4 letters are in the 7 first letters of the alphabet meaning that they are in our pile of tiles. There is a 4 out of 7 chance of picking one of those letters. (4/7)
(a) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a <u>5/7 chance</u> of either Event X or Event Y happening since tiles "A" and "C" are included in both events.
(b) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a <u>2/7 chance</u> of both X and Y happening since there are only 2 tiles that are the same in both events, "A" and "C". (We are only allowed to pick one tile)
(c) The complement of Event Y is 1-4/7=<u>5/7 chance</u>.
Answer:
Answer is D.
Step-by-step explanation:
![v^{2} =\frac{3P}{mn}\\](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%5Cfrac%7B3P%7D%7Bmn%7D%5C%5C)
Multiply both sides by m.
![mv^{2} =\frac{3P}{n}\\](https://tex.z-dn.net/?f=mv%5E%7B2%7D%20%3D%5Cfrac%7B3P%7D%7Bn%7D%5C%5C)
Divide both sides by
.
![m =\frac{3P}{nv^{2}}\\](https://tex.z-dn.net/?f=m%20%3D%5Cfrac%7B3P%7D%7Bnv%5E%7B2%7D%7D%5C%5C)
Hello!
I would say the second option, because it looks like the most reasonable one. The third and fourth options decrease, but we can see by the chart that in fact, the weight increases. Also, it wouldn't be the first option, because its showing that the wight is always constant and rate doesn't change. However, we can see that this is wrong and the rate actually does change. Therefore, the second option looks like the most reasonable for this chart.
Hope this helps!
Step-by-step explanation:
the picture isn't realistic but mathematically it's:
1) = 121°
2) = 59°