3 years ago

Find the quotient.

Mathematics

1 answer:

Sever21 [200]3 years ago

3 0

The answer to the question is B

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Write an equation in slope-intercept form of<br> the line that passes through (-6,4) and<br> (-1,2).

xz_007 [3.2K]

Answer:

Step-by-step explanation:

(-6 , 4) & (-1 , 2)

Slope = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$= \frac{2-4}{-1-[-6]}\\\\= \frac{-2}{-1+6}\\\\= \frac{-2}{5}$

m = -2/5 & (-6 , 4)

y -y1 = m(x -x1)

$y - 4 = \frac{-2}{5}(x - [-6])\\\\y - 4 = \frac{-2}{5}(x + 6)\\\\y - 4 = \frac{-2}{5}x + 6*\frac{-2}{5}\\\\y = \frac{-2}{5}x -\frac{12}{5}+4\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{4*5}{1*5}\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{20}{5}\\\\y=\frac{-2}{5}x+\frac{8}{5}$

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3 years ago

Raphael graphed the system of equations shown. y = – 3 y = x – 0.8 What is the best approximation for the solution to this syste

Ber [7]

Given ---›

y = -3

&

y = x - 0.8

So,
=> x = y + 0.8

=> x = -3 + 0.8

=> x = -2.2

Therefore, the best approximation for the solution to this system of equations is = (–2.2, –3)

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4 years ago

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Today only, a table is being sold for $279. This is 62% of its regular price. What was the price yesterday?

White raven [17]

Answer:

Step-by-step explanation:

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3 years ago

What are the solutions to the quadratic equation x^2-16=0

frutty [35]

Simplifying this, we get:
(x+4)(x-4) = 0
Now, to get 0, we can replace x for one of these things to make 0, so:
x can either be 4, or -4