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max2010maxim [7]
3 years ago
9

PLEASE HELP due in 5 minutes thank you!!

Mathematics
2 answers:
elena-s [515]3 years ago
7 0

Answer:

x = 180 - 76 - 63

x = 41°

Step-by-step explanation:

Sergio039 [100]3 years ago
4 0

Answer:

x =41

Step-by-step explanation:

The three angles form a straight line so they add to 180 degrees

76+ x+ 63 = 180

Combine like terms

139 + x = 180

Subtract 139 from each side

139-139 + x = 180-139

x =41

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What positive value of x makes the following equation true: 125 = x^3? Explain
alina1380 [7]

Answer: The correct answer is x=5

Step-by-step explanation:

x=2−5−−75​​=2−5−5i3​​=−2.5000−4.3301i

x=2−5+−75​​=2−5+5i3​​=−2.5000+4.3301i

x=5

Hoped I helped

can you mark me as brainliest

4 0
3 years ago
Find the solution to Y=-x^2+3 for X=-3,0, and 3
BabaBlast [244]

Answer:

3-,3,0,3

Step-by-step explanation:

7 0
3 years ago
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Evaluate the expression -2cd if a = -8 b = 2 c = -5 d = 6
Elza [17]

Answer:

60

Step-by-step explanation:

Replace c and d with -5 and 6.

-2*-5*6

-2*-5=10

10*6=60

The expression is equal to 60.

-hope it helps

5 0
2 years ago
As an estimation we are told 5 miles is 8km Convert 4 km to miles
puteri [66]

Answer: 2.5

Step-by-step explanation:

For this problem, we see that 4km is 1/2 of 8km.

So, we will have to find 1/2 of 5km.

1/2 of 5km = 2.5km

Your answer is 2.5km

4 0
3 years ago
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PLEASE HELP ME! I really need help y'all...
ikadub [295]

just a quick clarification, tis usually -4.9 and that's a rounded number to reflect earth's gravity on an object in motion, but -5 is close enough :)

\bf ~~~~~~\textit{initial velocity in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}\\ \qquad \textit{of the object}\\ h=\textit{object's height}\\ \qquad \textit{at "t" seconds} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf h(x)=-5(\stackrel{\mathbb{F~O~I~L}}{x^2-8x+16})+180\implies h(x)=-5x^2+40x-80+180 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x)=-5x^2+\stackrel{\stackrel{v_o}{\downarrow }}{40} x+\stackrel{\stackrel{h_o}{\downarrow }}{\boxed{100}}~\hfill

8 0
3 years ago
Read 2 more answers
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