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3 years ago

13

What positive value of x makes the following equation true: 125 = x^3? Explain

1 answer:

alina1380 [7]3 years ago

4 0

Answer: The correct answer is x=5

Step-by-step explanation:

x=2−5−−75=2−5−5i3=−2.5000−4.3301i

x=2−5+−75=2−5+5i3=−2.5000+4.3301i

x=5

Hoped I helped

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HELP NOW ASAP HURRY i don't got all day!!!!!!!!!!!!!

Anarel [89]

Answer:

15 3/4t^2 + 5 1/4

Explanation:

h(t)=-16t^2+400

We can add 400 then - 64 and show as 8^2

= h(t)=-16t^2+400 - 8^2

But we also need to change 16t^2;

We divide 64 into 16 = 16/64 =0.25

and show 16t^2 changes by 0.25 = 1/4

15 3/4t^2 + 400-64

Can now look like

15 3/4t^2 + 5 1/4

As 5 1/4 = 64 x 5 1/4 = 336

8 0

3 years ago

A^2 + b^2 + c^2 = 2(a − b − c) − 3. (1) Calculate the value of 2a − 3b + 4c.

Verdich [7]

Answer:

$2a - 3b + 4c = 1$

Step-by-step explanation:

Given

$a^2 + b^2 + c^2 = 2(a - b - c) - 3$

Required

Determine $2a - 3b + 4c$

$a^2 + b^2 + c^2 = 2(a - b - c) - 3$

Open bracket

$a^2 + b^2 + c^2 = 2a - 2b - 2c - 3$

Equate the equation to 0

$a^2 + b^2 + c^2 - 2a + 2b + 2c + 3 = 0$

Express 3 as 1 + 1 + 1

$a^2 + b^2 + c^2 - 2a + 2b + 2c + 1 + 1 + 1 = 0$

Collect like terms

$a^2 - 2a + 1 + b^2 + 2b + 1 + c^2 + 2c + 1 = 0$

Group each terms

$(a^2 - 2a + 1) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

Factorize (starting with the first bracket)

$(a^2 - a -a + 1) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$(a(a - 1) -1(a - 1)) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1) (a - 1)) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b^2 + b+b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b(b + 1)+1(b + 1)) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)(b + 1)) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c^2 + c+c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c(c + 1)+1(c + 1)) = 0$

$((a - 1)^2) + ((b + 1)^2) + ((c + 1)(c + 1)) = 0$

$((a - 1)^2) + ((b + 1)^2) + ((c + 1)^2) = 0$

Express 0 as 0 + 0 + 0

$(a - 1)^2 + (b + 1)^2 + (c + 1)^2 = 0 + 0+ 0$

By comparison

$(a - 1)^2 = 0$

$(b + 1)^2 = 0$

$(c + 1)^2 = 0$

Solving for $(a - 1)^2 = 0$

Take square root of both sides

$a - 1 = 0$

Add 1 to both sides

$a - 1 + 1 = 0 + 1$

$a = 1$

Solving for $(b + 1)^2 = 0$

Take square root of both sides

$b + 1 = 0$

Subtract 1 from both sides

$b + 1 - 1 = 0 - 1$

$b = -1$

Solving for $(c + 1)^2 = 0$

Take square root of both sides

$c + 1 = 0$

Subtract 1 from both sides

$c + 1 - 1 = 0 - 1$

$c = -1$

Substitute the values of a, b and c in $2a - 3b + 4c$

$2a - 3b + 4c = 2(1) - 3(-1) + 4(-1)$

$2a - 3b + 4c = 2 +3 -4$

$2a - 3b + 4c = 1$

7 0

3 years ago

Priam has pennies and dimes in a cup holder in his car. The total value of the coins is $4.21. The number of dimes is three less

aksik [14]

Answer:

40 dimes and 21 pennies.

Step-by-step explanation: 40 dimes equal 4.00 so just add 21 pennies

8 0

3 years ago

Read 2 more answers

A baker took 9 hours to bake 6 cakes how long does it take him to bake 1 cake?

AlexFokin [52]

Answer:

1.5 hours

Step-by-step explanation:

5 0

3 years ago

Help plssss and thank you

dimaraw [331]

Answer:

$y=\frac{1}{4}x +3$

Step-by-step explanation:

slope (rise over run) choose 2 points that are easy to figure out. Count up and over to get the slope

(0,3) and (4,4)

3 to 4 is 1

0 to 4 is 4

slope is 1/4

y intercept is b- so +3

y= $y=\frac{1}{4} x+3$

5 0

3 years ago