Question

Find the solution to Y=-x^2+3 for X=-3,0, and 3

Answer 1

For this case we must evaluate the following quadratic equation, $y = -x ^ 2 + 3,$ for $x = -3$, $x = 0$and $x = 3$

For $x = -3$:

$y = - (- 3) ^ 2 + 3\\y = -9 + 3 =\\y = -6$

For $x = 0$:

$y = - (0) ^ 2 + 3\\y = 0 + 3\\y = 3$

For $x = 3$:

$y = - (3) ^ 2 + 3\\y = -9 + 3\\y = -6$

Answer:

$(-3, -6)\\(0,3)\\(3, -6)$

Answer 2

Answer:

3-,3,0,3

Step-by-step explanation: