All categories

3 years ago

I need help with this if you get it right I will mark you as BRAINLEST

Mathematics

1 answer:

lina2011 [118]3 years ago

7 0

Answer:

the answer is A as it says shoe in the last one which immediately eliminates that option and as of for store b u only save 5 bucks

You might be interested in

Tom has 12.42 centimeters of yarn. If he wants to make the yarn into pieces that are 0.54 centimeters long, how many pieces can

natta225 [31]

Answer:

23 pieces of yarn

Step-by-step explanation:

12.42cm divided by 0.54cm = 23

pls mark brainliest....:)

5 0

3 years ago

Simplify expression (5xy^-6/x^4 y^-2)^2

ipn [44]

Here it is...........................

4 0

3 years ago

12.what is the probability that a boy and a girl chosen randsomly will be seniors?

zhenek [66]

$\frac{\textbf{1}}{\textbf{20}}$

Step-by-step explanation:

Probability= $\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}$

Probability for a randomly chosen girl to be senior= $\frac{\text{number of senior girls}}{\text{total number of girls}}$

Probability for a randomly chosen girl to be senior= $\frac{7}{8+11+9+7}=\frac{7}{35}=\frac{1}{5}$

Probability for a randomly chosen boy to be senior= $\frac{\text{number of senior boys}}{\text{total number of boys}}$

Probability for a randomly chosen girl to be senior= $\frac{9}{10+7+10+9}=\frac{9}{36}=\frac{1}{4}$

For two independent events,

Probability for both event 1 and event 2 to take place= $\text{probability of event 1} \times \text{probability of event 2}$

Since choosing boys and girls is independent,

Probability for both boy an girl chosen to be senior= $\text{probability for boy to be senior}\times\text{probability for girl to be senior}$

Probability for both boy and girl chosen to be senior= $\frac{1}{5} \times \frac{1}{4} = \frac{1}{20}$

So,required probability is $\frac{1}{20}$

3 0

3 years ago

Find the value of each variable.

kap26 [50]

Answer:

EF = 18 in. & m∠F = 134 °

Step-by-step explanation:

Hi there,

In order to find the length of side EF, you should realize that this is an <u>isosceles triangle</u>. We know that two sides and two angles of this type of triangle are equal to each other. We also know that the lengths of the sides opposite of the congruent angles are equal to each other. Thus, we proved that length of side EF is equal to the length of side FG.

Therefore, EF is 18 inches because FG is 18 inches.

In order to find m∠F, you need to know that the sum of the angles in a triangle add up to 180°. You add all of the known angle values and subtract it by 180°.

m∠E + m∠G + m∠F = 180°

23° + 23° + m∠F = 180°

46° + m∠F = 180°

m∠F = 134°

Hope this explanation helps you understand this problem. Cheers.

5 0

3 years ago

A random sample of 16 statistics examinations was taken. The average sample score was 76.2 with a sample variance of 144. The 99

dlinn [17]

99% confidence interval for the population average examination score is between a lower limit of 67.35 and an upper limit of 85.05. The correct option is C.

<h3>What is the margin of error in statistics?</h3>

The margin of error is a statistic that describes how much random sampling error there is in survey results. One should have less faith that a poll's findings would accurately reflect those of a population census the higher the margin of error.

The interval will be calculated as below:-

Confidence interval = mean +/- margin of error (E)

mean = 76.2

variance = 144

sd = sqrt(variance) = sqrt(144) = 12

n = 16

Degree of freedom (df) = n - 1 = 16- 1 = 15

Confidence level (C) = 99% = 0.99

Significance level = 1 - C = 1 - 0.99 = 0.01 = 1%

t-value corresponding to 15 df and 1% significance level is 2.95

The margin of error will be:-

E = t×sd/√n = 2.95 × 12/√16 = 8.85

The interval will be:-

Lower limit = mean - E = 76.2 - 8.85 = 67.35

Upper limit = mean + E = 76.2 + 8.85 = 85.05

Therefore, the 99% confidence interval for the population average examination score is between a lower limit of 67.35 and an upper limit of 85.05. The correct option is C.

To know more about margin of error follow

brainly.com/question/24289590

#SPJ1

4 0

2 years ago