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4 years ago

|x + 2|> 2 How would you graph this solution

Mathematics

1 answer:

Vilka [71]4 years ago

3 0

Answer:

Solving the inequality |x+2| > 2

X belongs to (- infinity, - 4) U ( 0, +infinity)

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The polynomial is a difference of perfect squares. Use the formula a2 – b2 = (a + b)(a – b) to factor completely.

mash [69]

Answer:

$81x^{2} -49\\(9x)^2-7^2\\(9x-7)(9x+7)$

6 0

3 years ago

Does this table show a proportional relationship? ________ Yes or No?

Colt1911 [192]

Answer:

Yes, the constant of proportionality is 1.5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

If f(x) = 7 + 4x and g(x)= 7x, what is the value of (f/g)(5)

andrew-mc [135]

The value of $(\frac{f}{g})(5)$ is $\frac{27}{35}$

Explanation:

Given that $f(x)=7+4x$ and $g(x)=7x$

The value of $(\frac{f}{g})(5)$ :

The value of $(\frac{f}{g})(5)$ can be determined by substituting x = 5 in the functions f(x) and g(x) and then dividing the terms, we get, the value of $(\frac{f}{g})(5)$

Thus, we have,

$(\frac{f}{g})(5)=\frac{f(5)}{g(5)}$

Substituting the value of x = 5 in the functions f(x) and g(x), we get,

$(\frac{f}{g})(5)=\frac{7+4(5)}{7(5)}$

Simplifying the terms, we have,

$(\frac{f}{g})(5)=\frac{7+20}{35}$

Adding the terms in numerator, we have,

$(\frac{f}{g})(5)=\frac{27}{35}$

Thus, the value of $(\frac{f}{g})(5)$ is $\frac{27}{35}$

8 0

3 years ago

URGENT!! Solve the following for θ, in radians, where 0≤θ<2π.

lidiya [134]

Answer: 0.93 radians & 2.21 radians

Step-by-step explanation:

$-4sin^2\theta-3sin\theta+5=0\\\\\text{Since this is not factorable, use the quadratic formula to find the roots:}\\\\sin\theta=\dfrac{-(-3)\pm \sqrt{(-3)^2-4(-4)(5)}}{2(-4)}\\\\\\.\quad=\dfrac{3\pm \sqrt{9+80}}{-8}\\\\\\.\quad=\dfrac{3\pm\sqrt{89}}{-8}\\\\\\.\quad=\dfrac{3\pm9.43}{-8}\\\\\\.\quad=\dfrac{12.43}{-8}\quad and\quad \dfrac{-6.43}{-8}\\\\\\.\quad=-1.55\quad and\quad 0.80\\\\\\\theta=sin^{-1}(-1.55)\quad and\quad \theta=sin^{-1}(0.80)$

$\theta=not\ valid\qquad and\quad \theta=0.927$

$\theta = 0.927\ radians\text{\ in the 1st quadrant and}\\\pi-0.927=2.21\ radians\text{\ in the 2nd quadrant}$

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4 years ago

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Two trains leave towns 976km apart at the same time and travel toward each other. one train travels 22 /kmh slower than the othe

PilotLPTM [1.2K]

Let s be the slow train, and s+22 be the faster one. Then:
976/s+s+22=4
976=8s+88
8s=888
s=111 kph as the slower train
s+22=133 kph as the faster train
☺☺☺☺

3 0

4 years ago