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2 years ago

Choose the expression that is equivalent to both −x/y and x/−y.

Mathematics

1 answer:

tensa zangetsu [6.8K]2 years ago

3 0

Answer:

1÷y/-x

Step-by-step explanation:

1÷y/-x

1×-x/y

-x/y

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What is the prime factorization for 36?<br> A. 22x32<br> B. 2x3x6<br> C. 6x6

ICE Princess25 [194]

Answer:

c. 6x6

Step-by-step explanation:

because 6x6 is =36

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In ΔMNO, the measure of ∠O=90°, the measure of ∠N=70°, and OM = 3.3 feet. Find the length of MN to the nearest tenth of a foot.

Aleks04 [339]

Answer:

Side MN = 3.5

Step-by-step explanation:

Side NO = 1.2011

Side OM = 3.3

Side MN = 3.51179

Angle ∠M = 20° = 0.34907 rad = π/9

Angle ∠N = 70° = 1.22173 rad = 7/18π

Angle ∠O = 90° = 1.5708 rad = π/2

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2 years ago

Calcutate these values:

Anettt [7]

A.84.5

B.76.26

C.402.5

D.390

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Hello please help posted picture of question

Naddika [18.5K]

The answer is b) because if a number is to the left of a point on a line, it is less than the value of the point. If n=5, m must be less than 5

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2 years ago

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What is the correct justification for the indicated steps?

yanalaym [24]

The given proof of De Moivre's theorem is related to the operations of

complex numbers.

<h3>The Correct Responses;</h3>

Step A: Laws of indices

Step C: Expanding and collecting like terms

Step D: Trigonometric formula for the cosine and sine of the sum of two numbers

<h3>Reasons that make the above selection correct;</h3>

The given proof is presented as follows;

$\mathbf{\left[cos(\theta) + i \cdot sin(\theta) \right]^{k + 1}}$

Step A: By laws of indices, we have;

$\left[cos(\theta) + i \cdot sin(\theta) \right]^{k + 1} = \mathbf{\left[cos(\theta) + i \cdot sin(\theta) \right]^{k} \cdot \left[cos(\theta) + i \cdot sin(\theta) \right]}$

$\left[cos(\theta) + i \cdot sin(\theta) \right]^{k} \cdot \left[cos(\theta) + i \cdot sin(\theta) \right] = \mathbf{\left[cos(k \cdot \theta) + i \cdot sin(k \cdot \theta) \right] \cdot \left[cos(\theta) + i \cdot sin(\theta) \right]}$

Step B: By expanding, we have;

$\left[cos(k \cdot \theta) + i \cdot sin(k \cdot \theta) \right] \cdot \left[cos(\theta) + i \cdot sin(\theta) \right] = cos(k \cdot \theta) \cdot cos(\theta) - sin(k \cdot \theta) \cdot sin(\theta) + i \cdot \left [sin(k \cdot \theta) \cdot cos(\theta) + cos(k \cdot \theta) \cdot sin(\theta) \right]$

Step D: From trigonometric addition formula, we have;

cos(A + B) = cos(A)·cos(B) - sin(A)·sin(B)

sin(A + B) = sin(A)·cos(B) + sin(B)·cos(A)

Therefore;

$cos(k \cdot \theta) \cdot cos(\theta) - sin(k \cdot \theta) \cdot sin(\theta) + i \cdot \left [sin(k \cdot \theta) \cdot cos(\theta) + cos(k \cdot \theta) \cdot sin(\theta) \right] = \mathbf{ cos(k \cdot \theta + \theta) + i \cdot sin(k \cdot \theta + \theta)}$

Learn more about complex numbers here:

brainly.com/question/11000934

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1 year ago

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