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Ira Lisetskai [31]
3 years ago
5

Solve the equation 2x^2-3x-6=0 give your answer correct to two decimal places

Mathematics
1 answer:
IRISSAK [1]3 years ago
6 0

Answer:

<h2>x = - 1.14 or x = 2.64</h2>

Step-by-step explanation:

2x² - 3x - 6 = 0

Using the quadratic formula

x =  \frac{ - b± \sqrt{ {b}^{2}  - 4ac} }{2a}

a = 2 , b = - 3 , c = 6

Substituting the values into the above formula

We have

x =  \frac{ -  - 3± \sqrt{ { - 3}^{2}  - 4(2)( - 6)} }{2(2)}

x =  \frac{3± \sqrt{9 +48 } }{4}

x =  \frac{3± \sqrt{57} }{4}

x =  \frac{3 -  \sqrt{57} }{4}  \:  \:  \:  \: or \:  \:  \:  \:  \: x =  \frac{3 +  \sqrt{57} }{4}

We have the final answer as

<h3>x = - 1.14 or x = 2.64</h3>

Hope this helps you

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What is the answer to 3x+2-x=11x-9
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3x+2−x=11x−9
Step 1: Simplify both sides of the equation.
3x+2−x=11x−93x+2+−x=11x+−9(3x+−)(2)=11x−9
(Combine Like Terms)
2x+2=11x−92x+2=11x−9

Step 2: Subtract 11x from both sides.
2x+2−11x=11x−9−11x−9x+2=−9

Step 3: Subtract 2 from both sides.
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Step 4: Divide both sides by -9.
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Hope it helps
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Read 2 more answers
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