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Brilliant_brown [7]
3 years ago
13

Francine has a picture whose length is 4/3 its width. She wants to enlarge the picture to have an area of 192 in2. What will the

dimensions of the enlarged picture be? Model the scenario and solve. Then, explain in at least one sentence your solution and include the reasonableness of your solution.
Mathematics
2 answers:
nikklg [1K]3 years ago
6 0
L=4W/3

A=LW, using L found above in this equation we have:

A=(4W)W/3

A=4W^2/3

3A=4W^2

3A/4=W^2

W=√(3A/4), we are told that A=192 in^2

W=√(3*192/4)

W=√144

W=12 in, since L=4W/3

L=4*12/3

L=16 in

So the length is 16 inches and the width is 12 inches.

LUCKY_DIMON [66]3 years ago
3 0

Answer:

The length of picture is 16 inches and width is 12 inches.

Step-by-step explanation:

Francine has a picture whose length is 4/3 its width.

Let the width of the picture be = w

Then its length would be = \frac{4w}{3}

She wants to enlarge the picture to have an area of 192 square inches.

This becomes: w*\frac{4w}{3}=192

4w^{2}= 576

w^{2} =144

This gives w = 12 inches.

We know that length*width =192

Length = \frac{192}{12} = 16

Hence, the length of picture is 16 inches and width is 12 inches.

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Answer:

The correct answer is yes, we can draw an isosceles triangle with only one 80° angle. NO this is not the only possibility.

Step-by-step explanation:

A triangle is a three sided figure. There are three types of triangles: Equilateral, Isosceles and Scalene triangle. The sum of angles in a triangle is 180°.

If all sides have equal length then it is an equilateral triangle. All angles of this triangle are equal.

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If none of the angles and sides are equal then we call it a scalene triangle.

Given one angle of the triangle is 80°.

There exists two possibilities. One, 80° is the equal angle and 80° is not the equal angle.

Required Case : 80° is not the equal angle, i.e. only one 80° angle.

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