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scoundrel [369]

3 years ago

13

Is this correct or Incorrect? Explain

1 answer:

Oduvanchick [21]3 years ago

7 0

Answer:

That all you would need to figure anything out. First thing you need to remember is that every triangle is 180 degrees total. Let's say one angle of a triangle 50 and the other is 35. If you were to add 5o and 35 together, you would get 85. Then I would do 180 - 85 and that would give you the remaining and missing angle. Hope this helps<3 !!

Step-by-step explanation:

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C(2, 5), D(3, 1)<br><br> Find the slope of the line that passes through each pair of points.

Tpy6a [65]

Slope=-4 or -4/1

Work:

(2, 5) (3, 1)
x1 y1. x2 y2

M= y2-y1/x2-x1
M= 1-5/3-2
M= -4/1
M=-4

5 0

3 years ago

How many solutions exist for the system of equations graphed below?

Anestetic [448]

Answer:

One

General Formulas and Concepts:

<u>Algebra I</u>

Reading a coordinate plane
Solving systems of equations by graphing

Step-by-step explanation:

If 2 lines are parallel, they will have no solution.

If 2 lines are the same, they will have infinite amount of solutions.

We see from the graph that the 2 lines intersect at one point, near x = 1.5.

∴ our systems has 1 solution.

4 0

2 years ago

Read 2 more answers

In order to join a yoga club there is a $100 annual fee and a $5 fee for each class you attend. write an equation in slope-inter

Alona [7]

The slope is 5x
Y=Mx+B
Y=5x+100

7 0

3 years ago

ITS TIMED PLEASE HELP

Lubov Fominskaja [6]

Answer:

The graph of the function $f(x)=\frac{1}{2}x^{2}-4x+5$ has a minimum located at (4,-3)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex of the parabola

If a > 0 the parabola open upward and the vertex is a minimum

If a < 0 the parabola open downward and the vertex is a maximum

In this problem

The coefficient a must be positive, because we need to find a minimum

therefore

Check the option C and the option D

Option C

we have

$f(x)=\frac{1}{2}x^{2}-4x+5$

Convert to vertex form

$f(x)-5=\frac{1}{2}x^{2}-4x$

Factor the leading coefficient

$f(x)-5=\frac{1}{2}(x^{2}-8x)$

$f(x)-5+8=\frac{1}{2}(x^{2}-8x+16)$

$f(x)+3=\frac{1}{2}(x^{2}-8x+16)$

$f(x)+3=\frac{1}{2}(x-4)^{2}$

$f(x)=\frac{1}{2}(x-4)^{2}-3$

The vertex is the point (4,-3) ( is a minimum)

therefore

The graph of the function $f(x)=\frac{1}{2}x^{2}-4x+5$ has a minimum located at (4,-3)

5 0

3 years ago

It costs $35 for one adult and two children to attend a show. It costs $60 for two adults and three children to attend the same

Zarrin [17]

Hello!

It cost an adult $15 to attend a show and $10 for a child.

Hope this helps!

6 0

2 years ago

Read 2 more answers