Vertical asymptotes occur when the denominator of a rational is 0, whilst not zeroing out the numerator, making the rational, undefined, in this case

Answer: 24.2° SouthWest
<u>Step-by-step explanation:</u>
First step: DRAW A PICTURE of the vectors from head to tail <em>(see image)</em>
I created a perpendicular from the resultant vector to the vertex of the given vectors so I could use Pythagorean Theorem to find the length of the perpendicular. Then I used that value to find the angle of the plane.
<u>Perpendicular (x):</u>
cos 35° = adjacent/hypotenuse
cos 35° = x/160
→ x = 160 cos 35°
<u>Angle (θ):</u>
sin θ = opposite/hypotenuse
sin θ = x/320
sin θ = 160 cos 35°/320
θ = arcsin (160 cos 35°/320)
θ = 24.2°
Direction is down (south) and left (west)
Answer:
The standard form of the line is 10x + 3y = 10
Step-by-step explanation:
First we need to find the slope of the equation, which we can do using the slope equation and the two points given: (3, 0) and (0, 10)
m(slope) = (y2 - y1)/(x2 - x1)
m = (10 - 0)/(0 -3)
m = 10/-3
Now we can write the equation in slope intercept form since we have the slope and the intercept.
y = mx + b
y = -10/3x + 10
Now we can manipulate the equation to get the standard form.
y = -10/3x + 10
10/3x + y = 10
10x + 3y = 30
The answer is c , between 52.43 and 64.20
9514 1404 393
Answer:
7x +5y = -5
Step-by-step explanation:
You can find the perpendicular line by swapping the x- and y-coefficients, and negating one of them. The new constant can be found by using the given point.
7x +5y = 7(-5) +5(6) = -5
The perpendicular line through (-5, 6) is ...
7x +5y = -5