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3 years ago

A regular hexagon is shown.

Mathematics

2 answers:

babymother [125]3 years ago

6 0

Answer:

14 in.

Step-by-step explanation:

well to start we have to know the relationships between angles, legs and the hypotenuse.

a: adjacent

o: opposite

h: hypotenuse

sin α = o/h

cos α= a/h

tan α = o/a

now as we know that the triangle that is formed has a right angle of 90 degrees, and two other angles that are 30 and 60 degrees.

We can know this by the properties of the hexagons

hexagon is formed by 6 equilateral triangles

equilateral triangles have 3 angles of 60 degrees

the triangle of the image is half of one of those triangles so it will have the upper angle of 30 and the other of 60

Now if we take the angle of 30 degrees and apply the following formula

sin α = o/h

cos 30 = a/h

0.866 = 12/h

h = 12/0.866

h = 13.8564

h = c

the nearest number is 14

slamgirl [31]3 years ago

4 0

Answer:14in on edg.

Step-by-step explanation:

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JulsSmile [24]

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<u>Solution:</u>

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We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$

Hence, the midpoint of the segment is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

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cestrela7 [59]

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Arte-miy333 [17]

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