Here is a photo of how to solve it
<em><u>Hey</u></em><em><u>!</u></em><em><u>!</u></em>
<em><u>They</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>adjacent</u></em><em><u> </u></em><em><u>angles</u></em><em><u>.</u></em>
<em><u>Both</u></em><em><u> </u></em><em><u>angles</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>common</u></em><em><u> </u></em><em><u>side</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>vertex</u></em><em><u>.</u></em>
<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Before:It's too short. Write at least 20 characters to explain it well.
After:It's too short. Write at least 20 characters to explain it well.
Answer:
True
Step-by-step explanation:
First start at B point than go to C point than go to A point
Answer & Step-by-step explanation:
This can be proven with the SAS theorem (side-angle-side)
With a perpendicular bisector, the line it bisects is cut directly in half. This creates two equal sides:
and it creates two 90° angles:
∠∠
And because of the reflexive property of congruence:
Side-Angle-Side.
:Done