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3 years ago

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The temperature outside Monday morning was -14. On Tuesday morning it was 4 degrees colder. Create an equation to show temperatu

re on Tuesday morning

1 answer:

Illusion [34]3 years ago

6 0

Answer:

Temperature on Tuesday morning is $-18^{o}$ .

Step-by-step explanation:

Temperature is the measure in degrees how cold or hot a substance is. The three scale of measurements are: Celsius, Fahrenheit, and Kelvin.

In the given question, temperature on Monday morning is -14 degrees. Since it was given that the temperature on Tuesday morning is 4 degrees colder than that of Monday, then;

Temperature on Tuesday = -14 + (-4)

= -14 -4

= -18

Therefore, the temperature on Tuesday morning is $-18^{o}$ .

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Answer:

39.9km a day

Step-by-step explanation:

Add up the four kilometers cycled and you should get 159.6km cycled in total. Divide that number by 4 to get 39.9km as a result. So she's wrong.

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3 years ago

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Un alumno multiplica un número por 32 en lugar de multiplicarlo por 23, obteniendo un producto mayor en 54 al producto original.

romanna [79]

Answer:

La suma de cifras del producto original es igual a 12.

Step-by-step explanation:

De acuerdo a la información proporcionada, si multiplicas un número "x" por 32 su resultado sería igual al producto original "y" más 54 dado que dice que se obtiene un producto mayor en 54 al producto original, lo que se puede expresar de la siguiente forma:

32x=y+54

Además, se puede inferir a partir del enunciado que si el número x se hubiera multiplicado por 23 el resultado habría sido el producto original que lo denominamos como "y", por lo que puedes decir que:

y=23x

Ahora puedes reemplazar y=23x en 32x=y+54 y despejar x:

32x=23x+54

32x-23x=54

9x=54

x=54/9

x=6

Finalmente, puedes reemplazar el valor de x en y=23x:

y=23x

y=23*6

y=138

Suma de cifras: 1+3+8 = 12

De acuerdo a esto, la respuesta es que la suma de cifras es igual a 12.

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3 years ago

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

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3 years ago

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