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nikdorinn [45]
3 years ago
6

The answer Is not A​

Mathematics
1 answer:
mote1985 [20]3 years ago
6 0

Answer:

  B.  6, 8, 10 2/3, 14 2/9, 18 26/27

Step-by-step explanation:

The recursive relation tells you the first term is 6, eliminating choice A immediately.

It also tells you each term is 4/3 the previous term, so the sequence cannot be a sequence of integers*, eliminating choices C and D.

If you do the math, you find the terms of Choice B are correct:

  • 6×4/3 = 8
  • 8×4/3 = 10 2/3
  • (10 2/3)×4/3 = 14 2/9
  • ...

_____

* Unless you start with a very large power of 3, repeatedly multiplying by 4/3 will eventually end with powers of 3 in the denominator and some multiple of powers of 2 in the numerator. Such a ratio cannot be an integer.

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