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Agata [3.3K]
3 years ago
9

Helpp! kind of clueless

Mathematics
2 answers:
spin [16.1K]3 years ago
5 0

Answer:

-11

Step-by-step explanation:

(a+b) +(c+d)

plug in

(-5+15)+(-9-12)

type in calculator

you will get your answer (-11)

Marta_Voda [28]3 years ago
3 0

Answer:

-11 (b)

Well basically plug the numbers into the equation. Than solve.

Step-by-step explanation:

So (-5 + 15) + (-9 + -12) is what you get when you plug in the values. Than do the math. 10 + -21 = -11

There you go. Hope this helped.

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The access code for a​ car's security system consists of digits. The first digit cannot be and the last digit must be . How many
Semenov [28]

Complete Question

The access code for a car's security system consists of 6 digits, the first digit cannot be 8 and the last digit must be odd, how many different codes are available

Answer:

There are 450000 possible different codes

<em></em>

Step-by-step explanation:

Given

Code = 6 digits

First = All but 8

Last = Odd

Required

Determine the possible number of codes

Analyzing each individual digit that makes up the code.

First: can be any of 0,1,2,3,4,5,6,7,9 ----- 9 possible numbers

Second, Third, Fourth and Fifth can be any of 0,1,2,3,4,5,6,7,8,9 since there's no restriction ----- 10 possible numbers

Last can be any of: 1,3,5,7,9 ----- 5 possible numbers

So, the number of possible selections is:

Selection = 9 * 10 * 10 * 10 * 10 *5

Selection = 450000

<em>Hence, there are 450000 possible different codes</em>

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3 years ago
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