$\bf \begin{cases}
(f\circ g)(x)=x^2-6x+8\\\\
(f\circ g)(x)=f(~~g(x)~~)\\\\
g(x)=x-3\\
\end{cases}
\\\\\\
\textit{now, one probability is }x^2-1
\\\\\\
f(x)=x^2-1\implies f(~~g(x)~~)=(x-3)^2-1
\\\\\\
f(~~g(x)~~)=(x^2-6x+9)-1\implies f(~~g(x)~~)=x^2-6x+8$

5 0

3 years ago

2 qurstions 100 points

Roman55 [17]

Answer:

1). 1.25 / 250 = .005M

.005 = 1 liter

2). (20)(.5) = 10M

have a good day, and be safe

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6 0

3 years ago

ratelena [41]

Amount Financed: $2,650
Finance Charge: $484.69
Number of Payments: 36

(Finance Charge)/(Amount Financed)*100$=($484.69)/($2,650)*100$
(Finance Charge)/(Amount Financed)*100$=(0.1829)*100$
(Finance Charge)/(Amount Financed)*100$=$18.29

In the row of number of Payments 36, we look for:
(Finance Charge)/(Amount Financed)*100$=$18.29, and we see to which annual porcentage rate it corresponds in the first row

Answer: 11.25%

7 0

3 years ago