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Vlad1618 [11]
3 years ago
14

The equation through the point (5,3) and is parallel the equation y=2/5x+7​

Mathematics
1 answer:
nignag [31]3 years ago
3 0

Answer:

Point - Slope Form: (y - 3) = 0.4(x - 5)

Slope - Intercept Form: y = 0.4x + 1

Step-by-step explanation:

Well if it's parallel, they have the same slope

Slope = 0.4

I'll do it in two forms:

Point - Slope Form: (y - 3) = 0.4(x - 5)

Slope - Intercept Form: y = 0.4x + b

3 = 2 + b

b = 1

y = 0.4x + 1

I might be wrong

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65,000 give me a thanks or brainiest answer if this helps! 
6 0
3 years ago
2)<br> A circle has a radius of 8 cm. What is its circumference?<br> 8 cm
egoroff_w [7]

Answer

16π cm ≈ 50.2655 cm

Step-by-step explanation

To find the circumference of a circle, we can use the equation C = 2πr.

C stands for the circumference while r stands for the radius. We can see that there is a proportional positive linear relationship between radius and circumference for all circles, and that to find circumference when we have a radius value, we multiply the radius value by 2π.

The value of π, also called pi, is a constant and is the ratio of a circle's circumference to its diameter (the diameter is twice the radius, hence the 2 in the equation). Note that π is a constant and applies to all circles because all circles are similar.

Since we know the value of r, or the radius, given as 8 cm in the question, we can plug this value into the equation C = 2πr from earlier.

C = 2πr (plug in 8 cm for the radius)

C = 2π * 8

C = 16π cm

Since the radius is in units of cm (centimeters), the circumference is also in units of cm (centimeters).

16π cm is the exact value of the circumference. However, if we want this circumference in decimal form, we would multiply 16 by the decimal form of π which is approximately 3.1416. Note that π actually has an infinite amount of decimals and that this 3.1416 is actually a rounded π value

C = 16π

C ≈ 16 * 3.1416

C ≈ 50.2655 cm rounded to four decimal places

6 0
3 years ago
If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?
kondaur [170]

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here, x_1=-8, y_1=-6, x_2=-4, y_2=-14

$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)

$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)

$P(x, y) =(-6, -10)

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Here, x_1=-6, y_1=-10, x_2=-8, y_2=-6

r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}

r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}

r=\sqrt{(-2)^{2}+(4)^{2}}

r=\sqrt{20} units

The standard form of the equation of a circle is

(x-a)^{2}+(y-b)^{2}=r^{2}, where (a, b) are center and r is the radius.

Here, center = (–6, –10) and r=\sqrt{20}

(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}

(x+6)^{2}+(y+10)^{2}=20

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

4 0
3 years ago
This set of points is on the graph of a function.
Liula [17]

If (a, b) is on the graph of a function f(x), then (b, a) is on the graph of the inverse.

We have points on the graph of a function: {(-3, 9), (-1, 1), (0, 0), (2, 4)}.

The points on the graph of the inverse: {(9, -3), (1, -1), (0, 0), (4, 2)}.

<h3>Answer: (4, 2), (0, 0), (1, -1).</h3>
7 0
3 years ago
Tan(60)x 20<br> please hurry!!
lana [24]

Answer:

6.4008

Step-by-step explanation:

7 0
3 years ago
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