Question

What is the y-value of the vertex of the function f(x)=-(x+8)(x-14)? 3 6 112 121

Answer 1

Answer:

121

Step-by-step explanation:

Given

f(x) = - (x + 8)(x - 14) ← expand factors using FOIL

     = - (x² - 6x - 112) ← distribute by - 1

     = - x² + 6x + 112

Given a quadratic in standard form. y = ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

$x_{vertex}$ = - $\frac{b}{2a}$

f(x) = - x² + 6x + 112 ← is in standard form

with a = - 1 and b = 6, thus

$x_{vertex}$ = - $\frac{6}{-2}$ = 3

Substitute x = 3 into f(x) for corresponding value of y

f(3) = - (3)² + 6(3) + 112 = - 9 + 18 + 112 = 121

vertex = (3, 121 ) ← with y = 121

Answer 2

Answer:

D. 121

Step-by-step explanation: