I am looking on the answers, and there is only one case, when a or b or c or d pass: 3|x-3| + 2 = 14. So I assume, that before two is plus. Then:
3|x-3|+2=14 |minus 2
3|x-3|=12 |divide 3
|x-3|=4
From absolute value definition you've got two ways:
x-3=4 or x-3=-4
x=7 or x=-1
And answer d) passes
Answer:
y=2.25x
Where y is the distance walked and x is time.
Answer:
0.4
Step-by-step explanation:
15 = 5p - 13
-13 = 5p -13
---------------- ( subtract 13 on both sides )
<u> 2 = 5p</u>
5 = 5p
---------------- ( divide 2 by 5 )
p = 0.4
( p equals 0.4 )
