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2 years ago

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Regina has wet weather on about 3/10 of the days in a year. It has wet weather on about four times as many days as it has fog. O

n what fraction of the days of the year does Regina have fog?
Please answer and show the work how you got the answer.

1 answer:

salantis [7]2 years ago

5 0

I would have to say 4/10. hope this helps

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When x = 2, y = 50 and when x = 4, y = 100. Which direct variation equation can be used to model this function?

Karolina [17]

Well, let's first write these as points.

( 2 , 50 )

( 4 , 100 )

We can see that when "x" is reduced by 2, "y" is reduced by 50. This means that if we reduce "x" by 1, "y" will be reduced by 25. Thus, we can say that if "x" is 1, "y" will be 25.

( 1 , 25 )

What we know that 25 * 1 = 25, and that 2 * 25 = 50. We can see that multiplying "x" by 25 will give us our "y". We can now write this as an equation.

y = 25x

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Alex777 [14]

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2 years ago

Which expression is equivalent to −19y+13 ?

Vikki [24]

The first thing you should do in this case is to write the expression correctly:
- (1/9) y + (1/3)
Now, we take out common factor (1/9) obtaining:
1/9 (-y + 3)
Let's check:
1/9 (-y + 3)
-1/9y + 3/9
-1/9y + 1/3
OK
Answer:
An expression equivalent is:
1/9 (-y + 3)

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2 years ago

Read 2 more answers

Either Table A or Table B shows a proportional relationship.

oee [108]

Table B of course they follow by the order instead of table A

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2 years ago

John, Jim and Joe each went for a medical examination. Their combined height was 5.25 m. If John was 12 cm shorter than Jim and

kolezko [41]

The 5.25 m combined height of John, Jim, and Joe, the 12 cm height difference between John and Jim and the 0.09 m difference in height between Jim and Joe, indicates that solution to the word problem is Joe was 1.73 meters tall

<h3>What is a word problem?</h3>

A word problem is a presentation of a math problem using verbal description rather than numbers, variables and operators.

The combined height of John, Jim and Joe = 5.25 m

John's height = Jim's height - 12 cm = Jim's height - 0.12

Jim's height = Joe's height + 0.09 m

Let <em>h </em>represent Joe's height, we get;

Jim's height = h + 0.09

John's height = h + 0.09 - 0.12 = h - 0.03

John's height = h - 0.03

The sum of the heights is therefore; h + h + 0.09 + h - 0.03 = 3·h + 0.06

The sum of their heights = Their combined height = 5.25 meters

Therefore; 3·h + 0.06 = 5.25

h = (5.25 - 0.06)/3 = 1.73

Joe's height, <em>h</em> = 1.73 meters

Jim's height = 1.73 + 0.09 = 1.82

Jim's height = 1.82 meters

John's height = 1.73 - 0.03 = 1.7

John's height is 1.7 meters

Joe was 1,73 meters tall

Learn more about mathematics word problems?

brainly.com/question/19386917

#SPJ1

4 0

1 year ago