Answer:
Option A. one rectangle and two triangles
Option E. one triangle and one trapezoid
Step-by-step explanation:
step 1
we know that
The area of the polygon can be decomposed into one rectangle and two triangles
see the attached figure N 1
therefore
Te area of the composite figure is equal to the area of one rectangle plus the area of two triangles
so
![A=(8)(4)+2[\frac{1}{2}((8)(4)]=32+32=64\ yd^2](https://tex.z-dn.net/?f=A%3D%288%29%284%29%2B2%5B%5Cfrac%7B1%7D%7B2%7D%28%288%29%284%29%5D%3D32%2B32%3D64%5C%20yd%5E2)
step 2
we know that
The area of the polygon can be decomposed into one triangle and one trapezoid
see the attached figure N 2
therefore
Te area of the composite figure is equal to the area of one triangle plus the area of one trapezoid
so
Answer:
33.75 or rounded to the nearest tenth: 33.8
Answer: It would be a Constant variable.
Hope this helps!
Think of a circle. We know it (and all circles) measure 360°. If you think about bisecting that circle, you would divide its 360° by 2, which results in 180°. The circle becomes a half-circle after being bisected, and its straight side (a straight angle) is 180°.
I've attached a diagram illustrating this.
Answer:
11 in
Step-by-step explanation:
Area of a square is L^2
where L is length.
L^2 = 121 in^2
FIND THE SQUARE ROOT OF BOTH SIDES (including in^2).
L= 11 in.
side = 11 in
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