We use the law of Cosines to find b=AC opposite B
![b^2 = a^2 + c^2 - 2 a c \cos B](https://tex.z-dn.net/?f=b%5E2%20%3D%20a%5E2%20%2B%20c%5E2%20-%202%20a%20c%20%5Ccos%20B)
We know all the sides of triangle ABM so we can use the law of Cosines, this time to solve for ![a c \cos B](https://tex.z-dn.net/?f=a%20c%20%5Ccos%20B)
![m^2 = (a/2)^2 + c^2 - a c \cos B](https://tex.z-dn.net/?f=m%5E2%20%3D%20%20%28a%2F2%29%5E2%20%2B%20c%5E2%20%20-%20a%20c%20%5Ccos%20B)
![ac \cos B = a^2/4 + c^2 - m^2](https://tex.z-dn.net/?f=%20ac%20%5Ccos%20B%20%3D%20a%5E2%2F4%20%2B%20c%5E2%20-%20m%5E2)
![b^2 = a^2 + c^2 - a^2/2 - 2 c^2 + 2m^2 = a^2/2 - c^2 + 2m^2](https://tex.z-dn.net/?f=b%5E2%20%3D%20a%5E2%20%2B%20c%5E2%20-%20a%5E2%2F2%20-%202%20c%5E2%20%2B%202m%5E2%20%3D%20a%5E2%2F2%20-%20c%5E2%20%2B%202m%5E2)
Substituting,
![b^2 = 8^2/2 - 5^2 + 2(4^2) = 32 - 25 + 32 = 39](https://tex.z-dn.net/?f=b%5E2%20%3D%208%5E2%2F2%20-%205%5E2%20%2B%202%284%5E2%29%20%3D%2032%20-%2025%20%2B%2032%20%3D%2039)
![b=\sqrt{39}](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B39%7D)
Answer: AC=√39
what do you need to know? maybe i can answer the question :)
![2 \frac{1}{8} +2 \frac{1}{4} =4 \frac{3}8}](https://tex.z-dn.net/?f=2%20%5Cfrac%7B1%7D%7B8%7D%20%2B2%20%5Cfrac%7B1%7D%7B4%7D%20%3D4%20%5Cfrac%7B3%7D8%7D%20)
![\frac{3}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B8%7D%20)
is less than .5 so you would round down to 4
So my guess since you did not provide the choices is about 4 hours.
Answer:
So the answer would be 9
Step-by-step explanation:
3*6=9
Answer:
340 songs, 17000/50 = 340 lol