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kondor19780726 [428]
3 years ago
14

Need help with this I don't understand it​

Mathematics
2 answers:
Bumek [7]3 years ago
7 0

Answer:

2 1/4

Step-by-step explanation:

6/4+3/4= 9/4= 2 1/4

Ne4ueva [31]3 years ago
6 0

Answer:

The correct answer would be 2 1/4.

Step-by-step explanation:

6/4+3/4= 2.25

2.25 is equal to 2 1/4

Brainliest?

Hail Hydra!

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Find an equation of the plane. the plane through the point (3, −8, −4) and parallel to the plane 2x − y − z
Marina86 [1]
Geggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg like yuhh
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3 years ago
A classmate simplifies the expression in exercise 1. is the expression he wrote equivalent to the original expression? explain.
AlladinOne [14]
Excercise 1:

No, this is not simplified fully. The full answer would be <span>−7dk+14d−21k</span>−7, not <span>14d - 9 - 21k - 7dk + 2. So, it is not equivalent.
</span><span>
Excercise 4:
</span><span>7dk (2 - 3 - 1) - 7
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Just multiply 7dk into (2) (-3) and (-1)
you'd get:
<span><span>−<span>14dk</span></span>+</span>−<span>7 after simplifying it fully.
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p = parameter
w = width

w+2.75

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Answer to the last one:

w = 6.125</span>
4 0
3 years ago
20 Is 80 percent of what number?<br> A 21<br> В 22<br> С 24<br> D 25
gogolik [260]

Answer:

D. 25

Step-by-step explanation:

If this helps, please mark this as brainliest

6 0
3 years ago
Read 2 more answers
I need help 5th grade​
Trava [24]
6 5/6 just subtract 2 from the whole (8)
6 0
3 years ago
Read 2 more answers
A small regional carrier accepted 23 reservations for a particular flight with 20 seats. 14 reservations went to regular custome
MrRissso [65]

Answer:

- The probability that overbooking occurs means that all 8 non-regular customers arrived for the flight. Each of them has a 56% probability of arriving and they arrive independently so we get that  

P(8 arrive) = (0.56)^8 = 0.00967

- Let's do part c before part b. For this, we want an exact booking, which means that exactly 7 of the 8 non-regular customers arrive for the flight. Suppose we align these 8 people in a row. Take the scenario that the 1st person didn't arrive and the remaining 7 did. That odds of that happening would be (1-.56)*(.56)^7.

Now take the scenario that the second person didn't arrive and the remaining 7 did. The odds would be  

(0.56)(1-0.56)(0.56)^6 = (1-.56)*(.56)^7. You can run through every scenario that way and see that each time the odds are the same. There are a total of 8 different scenarios since we can choose 1 person (the non-arriver) from 8 people in eight different ways (combination).  

So the overall probability of an exact booking would be [(1-.56)*(.56)^7] * 8 = 0.06079

- The probability that the flight has one or more empty seats is the same as the probability that the flight is NOT exactly booked NOR is it overbooked. Formally,  

P(at least 1 empty seat) = 1 - P(-1 or 0 empty seats)  

= 1 - P(overbooked) - P(exactly booked)

= 1 - 0.00967 - 0.06079  

= 0.9295.

Note that, the chance of being both overbooked and exactly booked is zero, so we don't have to worry about that.

Hope that helps!

Have a great day :P

7 0
3 years ago
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