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satela [25.4K]
3 years ago
7

K over x = w over v solve for x

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
6 0
\frac{k}{x} = \frac{w}{v} Multiply both sides by v
<span>\frac{kv}{x} = w   Multiply both sides by x
</span>kv = wx   Divide both sides by w
<span>\frac{kv}{w} = x   Switch the sides to make it easier to read
</span>x = <span>\frac{kv}{w} </span>
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Help me answer <br> Expand 3p(p+5)
pantera1 [17]

Answer:

3p² + 15p

Step-by-step explanation:

We use distributive property to distribute 3p to each of the terms:

3p · p = 3p²

3p · 5 = 15p

3p² + 15p

3 0
3 years ago
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you sell bracelets for $2 each and necklaces for $3 each at a local flea market. You collect$95, selling a total of 37 jewelry i
Alex787 [66]
The system of linear equations that may be used in order to solve this problem is as follows:

x + y = 37
2x + 3y = 95

This is considering that x is the number of bracelets sold and y is the number of necklaces.

The values of x and y in the equation are 16 and 31, respectively.

Thus, the answer is 16 bracelets and 21 necklaces.
4 0
3 years ago
Can anyone help me with this answer.
Kitty [74]

Answer:

<u>27 cm²</u>

Step-by-step explanation:

Shaded Area = Area ABCE - Area AED

  • S.A. = 6 x 6 - 1/2 x 3 x 6 [DE = 1/2AB = 1/2 X 6 = 3]
  • S.A. = 36 - 9
  • S.A. = <u>27 cm²</u>
8 0
2 years ago
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How do I solve this please? Can SOMEONE please help me this and the ones Iposted on my page.
vagabundo [1.1K]

Answer: \dfrac{15}{64}

Step-by-step explanation:

Given

Inside radius of figure r_1=\frac{14}{2}=7\ ft

Outside radius of figure r_2=\frac{16}{2}=8\ ft

Area of outside region is A_1=\pi (8^2)

Area of inside region A_2=\pi (7)^2

Area of shaded region A_1-A_2

Probability that point lies inside the shaded region is

\Rightarrow P=\dfrac{A_1-A_2}{A_1}\\\\\Rightarrow P=\dfrac{\pi (8^2-7^2)}{\pi 8^2}\\\\\Rightarrow P=\dfrac{64-49}{64}\\\\\Rightarrow P=\dfrac{15}{64}

5 0
3 years ago
10 points!!!!! Do 14 and 15 only hurry please.
Aleksandr [31]

Answer:

8. x = 16

9. x = 10

14.

m ∠RSU = 130°

m ∠UST = 50°

15.

m ∠RSU = 124°

m ∠UST = 56°

Step-by-step explanation:

8.

Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF

That is , (x + 15)° = 31°

                x = 31 - 15 =  16

9.

Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF

That is ,

           (6x - 4)° = 56°

            6x = 56 + 4

               6x = 60

                 x = 10

14.

13x + 5x = 180°                       [straight line angles ]

18x = 180

x = 10

m ∠RSU = 130°

m ∠UST = 50°

15.

4x + 12 + 2x = 180°                       [ straight line angles]

6x = 180 - 12

6x = 168

x = 28

m ∠RSU = 4(28) + 12 = 112 + 12 = 124°

m ∠UST = 2(28) = 56°

3 0
2 years ago
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