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bogdanovich [222]
3 years ago
12

Please answer correctly !!!!!!! Will mark brainliest answer !!!!!!!!!!!!

Mathematics
1 answer:
Lunna [17]3 years ago
3 0

Answer:

Its A

Thats because if you draw it then you will find that the vertex is 8, -8

A,

(8, -8)

THANKS FOR GIVING BRAINLIEST

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4 0
3 years ago
What is the solution to -3m = -15
Leviafan [203]

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3 0
3 years ago
Read 2 more answers
A can of beans has surface area 320cm squared . Its height is 14 cm. What is the radius of the circular​ top?
Ratling [72]

Steps:

All cans take on the shape of a cylinder, unless you have seen interesting shape of cans like a starfish.

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SA = 2πr2 + 2πrh

 

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h = height

 

Since we know the surface area and height, we can plug them in.  Note that we can factor out the 2π.  You will see why we factor out 2π rather than 2πr.

 

2π(r2 + (20)r) = 396

 

2π(r2 + 20r) = 396

 

 

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r2 + 20r = 63.025    

 

 

Subtract 63.025 on both sides of the equation.

 

r2 + 20r - 63.025 = 0

 

 

Use the quadratic formula to solve for r:

 

r = (-b ± √(b2 - 4ac)) / 2a

 

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a = 1

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Plug in these values into the formula.  You should get two solutions because of the plus/minus sign.  Accept the positive value of r.

Please mark brainliest

<em><u>Hope this helps.</u></em>

4 0
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Given a triangle with vertices P(-9,7), Q(-3,7), and R(-3,1), and S is the midpoint of PQ and T is the midpoint of QR, what is t
Natalija [7]
Check the picture below.

so we know S is the midpoint of PQ, and T is the midpoint of QR, thus

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&P&(~ -9 &,& 7~) &#10;%  (c,d)&#10;&Q&(~ -3 &,& 7~)&#10;\end{array}\quad&#10;%   coordinates of midpoint &#10;\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)&#10;\\\\\\&#10;S=\left( \cfrac{-3-9}{2}~,~\cfrac{7+7}{2} \right)\implies S=(-6,7)\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&Q&(~ -3 &,& 7~) &#10;%  (c,d)&#10;&R&(~ -3 &,& 1~)&#10;\end{array}&#10;\\\\\\&#10;T=\left(\cfrac{-3-3}{2}~,~\cfrac{1+7}{2}  \right)\implies T=(-3,4)

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\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&S&(~ -6 &,& 7~) &#10;%  (c,d)&#10;&T&(~ -3 &,& 4~)&#10;\end{array}\\\\\\ &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;ST=\sqrt{[-3-(-6)]^2+[4-7]^2}\implies ST=\sqrt{(-3+6)^2+(4-7)^2}&#10;\\\\\\&#10;ST=\sqrt{3^2+(-3)^2}\implies ST=\sqrt{18}\implies ST=\sqrt{9\cdot 2}&#10;\\\\\\&#10;ST=\sqrt{3^2\cdot 2}\implies ST=3\sqrt{2}

5 0
3 years ago
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