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wel
3 years ago
12

A factory's worker productivity is normally distributed. one worker produces an average of 77 units per day with a standard devi

ation of 22. another worker produces at an average rate of 66 units per day with a standard deviation of 19.
a. what is the probability that in a single day worker 1 will outproduce worker 2?
Mathematics
1 answer:
VLD [36.1K]3 years ago
4 0
One worker<span> produces an average of 84 units per </span>day<span> with a street </span>What is the probability<span> that in any </span>single day worker 1 will outproduce worker 2<span>? A) 0.1141.
</span>
Answer, factory worker productivity<span> is </span>normally distributed<span>. </span>One worker produces<span> an </span>average<span> of 75 </span>units per day<span> with a standar, day with a </span>standard deviation<span> of 20. </span>Another worker produces<span> at an </span>average rate<span> of 65 </span><span>per day.

</span>
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Evaluate the given algebraic expression for x= 8.<br> 6 + 8x
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70

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8(8) + 6 = 64 + 6 = 70

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3 years ago
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7 0
4 years ago
HH represents the height of the tree (in centimeters), t tt years since Renata moved in. H = 210 + 33 t H=210+33tH, equals, 210,
Jet001 [13]

Answer:

Therefore the rate of growth of the tree is 33 cm/ yr.

Step-by-step explanation:

Given that,

The height of the tree is

H= 210 +33t

Here H represent the height of tree in cm and t is time in year.

The rate of growth is the first order derivative of the H with respect to time.

i.e The rate of growth  =\frac{dH}{dt}

∴H= 210 +33t

Differentiating with respect to t

\frac{dH}{dt} =0 +33

\Rightarrow \frac{dH}{dt}=33

Therefore the rate of growth of the tree is 33 cm/ yr.

7 0
3 years ago
What is 0.55 hectometers expressed in decimeters? a. 550 dm b. 5.5 dm c. 55 dm d. 0.00055 dm please select the best answer from
zubka84 [21]

The correct option is a. 550 dm.

The 0.55 hectometers expressed in decimeters are 550 dm.

<h3>What is unit conversion?</h3>

Unit conversion is a multi-step process that involves multiplying or dividing by a numerical factor and, more specifically, a conversion factor.

  • The process may also necessitate selecting the appropriate amount of significant digits and rounding.
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2 years ago
No links I can interpret numerical expressions without evaluating them.
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