Answer:
(0, -2)
Step-by-step explanation:
Step 1: Write equation in slope-intercept form
-3y = 6 - 2x
y = -2 - 2/3x
Step 2: Find y-int
y = -2 -2/3(0)
y = -2
(0, -2)
It depends on the value of the discriminant of the quadratic.
If you are familiar with the quadratic formula...
x=(-b±√(b^2-4ac))/(2a)
The part under the radical sign (b^2-4ac) is called the discriminant of the quadratic (of the form ax^2+bx+c)
If the discriminant is less than zero there are no REAL solutions (however there are two imaginary solutions)
If the discriminant is equal to zero, there is just one solution
If the discriminant is greater than zero, there are two real solutions.
So depending on context, if you are to exclude imaginary solutions (which we often do) you can have 0,1, or 2 real solutions.
However you will NEVER have three solutions. (real or imaginary)
Hope this helps u out :D
Answer:
The GCF is 3w
Step-by-step explanation:
You have to find the GCF of
6w^3, 3w^2, 9w
You can start with 3. Then get:
6w^3/3 = 2w^3
3w^2/3 = w^2
9w/3 = 3w
The following factor is w. It has to have an exponent of one, as it the smallest exponent present in the 3 numbers:
2w^3/w = 2w
w^2/w = w
3w/w = 3
Expression:
6w^3 - 3w^2 - 9w= 3w(2w^2 - w - 3)
The GCF is 3w.
Answer:
A= -2,4 B=2,4 C= 2,5
Step-by-step explanation:
I tried my best even though C doesn't have a solid answer but A and B are correct so go off that.
Answer: HI!
Step-by-step explanation:
