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3 years ago

If the volume of the pyramid is 72cm, what is its height in cm?

Mathematics

2 answers:

nydimaria [60]3 years ago

5 0

it is b.9 because u have to multiply (w×h×l)/3

AleksAgata [21]3 years ago

5 0

Answer:

Step-by-step explanation:

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What is the constant of proportionality in the equation y=12.9x? Enter your answer as a decimal

forsale [732]

Answer:

The constant of proportionality would just be 12.9.

Step-by-step explanation:

This equation is already simplified enough to were the constant of proportionality is just the number attached to the x.

3 0

3 years ago

What is the percent of 28 of the 32

Scrat [10]

Step by step explanation = 76

7 0

3 years ago

Evaluate the surface integral ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing With Upper S f (x

kykrilka [37]

Parameterize $S$ by

$\vec s(u,v)=6\cos u\sin v\,\vec\imath+6\sin u\sin v\,\vec\jmath+6\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take a normal vector to $S$ ,

$\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}=36\cos u\sin^2v\,\vec\imath+36\sin u\sin^2v\,\vec\jmath+36\cos v\sin v\,\vec k$

which has norm

$\left\|\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}\right\|=36\sin v$

Then the integral of $f(x,y,z)=x^2+y^2$ over $S$ is

$\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\iint_S\left((6\cos u\sin v)^2+(6\sin u\sin v)^2\right)\left\|\frac{\partial\vec s}{\partial v}\times\frac{\partial\vec s}{\partial u}\right\|\,\mathrm du\,\mathrm dv$

$=\displaystyle36^2\int_0^{\pi/2}\int_0^{2\pi}\sin^3v\,\mathrm du\,\mathrm dv=\boxed{1728\pi}$

6 0

3 years ago

M∠Q = m∠R = m∠S = 40 POINTS!!!!!!!

Marizza181 [45]

9514 1404 393

Answer:

∠Q = 89°

∠R = 123°

∠S = 91°

Step-by-step explanation:

It seems easiest to start by finding the measures of each of the arcs. The measure of an arc is double the measure of the inscribed angle it subtends.

arc QRS = 2·∠P = 114°

So, ...

arc QR = arc QRS - arc RS = 114° -41° = 73°

The total of the arcs around the circle is 360°, so ...

arc PQ = 360° -arc PS -arc QRS

arc PQ = 360° -137° -114° = 109°

∠Q = (1/2)(arc RS + arc PS) = (1/2)(41° +137°)

∠Q = 89°

∠R = (1/2)(arc PS +arc PQ) = (1/2)(137° +109°)

∠R = 123°

∠S = (1/2)(arc PQ +arc QR) = (1/2)(109° +73°)

∠S = 91°

7 0

2 years ago

Solve for p. 2(p + 1) = 16 What is the answer?

Mashutka [201]

Divide both sides by 2

p + 1 = 16/2

Simplify 16/2 to 8

p + 1 = 8

Subtract 1 from both sides

p = 8 - 1

Simplify 8 - 1 to 7

p = 7

4 0

3 years ago

Read 2 more answers