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UNO [17]
3 years ago
11

En una caja de muchos bombones hay hasta tres sabores de ellos. ¿Cuántos se deben extraer como mínimo al azar para obtener con s

eguridad 5 bombones de un mismo sabor?
Mathematics
1 answer:
avanturin [10]3 years ago
3 0

Answer:

At least 13 chocolates must be removed

Step-by-step explanation:

If there are three flavors, the probability of drawing 1 would be: 1

1/3 = 0.333

Which means, that every 3 attempts, theoretically you should do 1 of each, but how they ask for 5 chocolates of each would be:

3 * 5 = 15

At least 15 chocolates must be extracted to theoretically guarantee 5 chocolates each, but how we are interested in knowing is that a single flavor has 5 chocolates, so we discard the last two chocolates that represent the other two flavors

Therefore, for there to be safely 5 chocolates of the same flavor, at least 13 chocolates must be removed.

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I have no clue to what I even need to do.
Gre4nikov [31]

\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ \cline{1-1} \theta =\frac{3\pi }{2}\\ s=\frac{5\pi }{2} \end{cases}\implies \cfrac{5\pi }{2}=r\cdot \cfrac{3\pi }{2}

\bf \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{3~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\cdot \cfrac{5~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=r\implies \cfrac{5}{3}=r

4 0
3 years ago
Will give brainliest to right answer please help!! 15 points -A sample of a radioactive isotope had an initial mass of 370 mg
Alex777 [14]

Answer:

78 mg

Step-by-step explanation:

370 mg - 110 mg = 260 mg (amount decayed in the 8 total years)

260 mg ÷ 8 years = 32.5 mg decayed per year

32.5 × 9 years (years between 2008 and 2017) = 292.5 mg

370 mg - 292.5 mg = 77.5 mg, rounded to 78 mg

4 0
3 years ago
Read 2 more answers
A circle has its center at (0,0) and passes through the point (0,9). What is the standard equation of the circle?
Alexxandr [17]

Answer:

x^2+y^2=9^2

Step-by-step explanation:

The standard equation of a circle is:

(x-h)^2+(y-k)^2=r^2

Where the center of a circle is (h,k) and r is the radius of the circle.  In this case because a circle is equidistant from the center and we have a point where it passes through 9 that means that the radius is 9.  However, since the standard equation states that we must write r in the form of r^2 this means that r^2=9^2.  Therefore by plugging in the values we have:

(x-0)^2+(y-0)^2=9^2\\\\x^2+y^2=9^2

7 0
3 years ago
Can some one help me match these ?
Anastaziya [24]
This is the order....

8 0
3 years ago
What the answer I don’t know it
meriva
The answer is B since a negative number being subtracted cancels out and becomes a number, for example: since its -(-3) it becomes positive.
5 0
3 years ago
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