The answer to the problem is A
Step-by-step explanation:
b^2-4b+3=0
b²-3x-b+3=0
b(b-3)-1(b-3)=0
(b-3)(b-1)=0
either
b=3 or b=1
.
2n^2 + 7 = -4n + 5
2n²+4n+7-5=0
2n²+4n+2=0
2(n²+2n+1)=0
(n+1)²=0/2
:.n=-1
.
x - 3x^2 = 5+ 2x - x^2
0=5+ 2x - x^2-x +3x^2
0=5+x+2x²
2x²+x+5=0
comparing above equation with ax²+bx +c we get
a=2
b=1
c=5
x={-b±√(b²-4ac)}/2a ={-1±√(1²-4×2×5)}/2×1
={-1±√-39}/2
Hello!
In geometry there are three dimensions.
Something that is one dimensional is neither flat, wide, or tall. It is just a line.
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Something two dimensional is flat and wide but has no height. An example of this is a square.
Something three dimensional is wide and tall, and has flat faces. An example is a cube.
To answer your question something one dimensional is something that is not flat, wide, or tall, such as a line.
Hope this helped!
A natural number is a positive integer, example, 1,2,5,299 etc.
A rational number is a number that can be expressed as a fraction of integers, such as 245/127, 1/2, 5/1,8/1,...
Since a natural number can be expressed as a fraction of integers, so
a natural number IS a rational number.
All rectangles are parallelograms. Hope this helps.