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Aleksandr-060686 [28]
3 years ago
8

You buy 3 pounds of lunch meat and pay $21.75.

Mathematics
2 answers:
Burka [1]3 years ago
8 0

Answer:

t = $7.25p

Hope this helps :)

harkovskaia [24]3 years ago
6 0

Answer:

= $7.25p

Divide $21.75 by 3

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The length of CD is 12 units C’D’ is the image of CD under a dilation with a scale factor of n.Which of these are true?
Korvikt [17]

Answer: FIrst option, Fourth option and Fifth option.

Step-by-step explanation:

First it is important to know the definition of "Dilation".

A Dilation is defined as a transformation in which the Image (which is the figure obtained after the transformation) and the Pre-Image (this is the original figure, before the transformations) have the same shape, but their sizes are different.

If the length of CD is dilated with a scale factor of "n" and it is centered at the origin, the length C'D' will be:

C'D'=nCD=(n)(12\ units)

Therefore, knowing this, you can determine that:

1. If n=\frac{3}{2} , you get:

C'D'=(\frac{3}{2})(12\ units)=18\ units

2. If n=4, then the length of C'D' is:

C'D'=(4)(12\ units)=48\ units

3. If n=8, then:

C'D'=(8)(12\ units)=96\ units

4. If n=2, then, you get that the lenght of C'D' is:

C'D'=(2)(12\ units)=24\ units

5. If n=\frac{3}{4}, the length of C'D' is the following:

C'D'=(\frac{3}{4})(12\ units)=9\ units

8 0
3 years ago
Please help me!!!!!!!!!
bagirrra123 [75]
F(-2)+g(5) = 3(-2) -1 + (-5) + 6
f(-2)+g(5) = -6 -1 - 5 + 6
f(-2)+g(5) = -6
5 0
3 years ago
25 POINTS AND BRAINLIEST PLEASE HELP ASAP
dexar [7]
M is a midpoint of BC so:

M=\left(\dfrac{\boxed{2}\boxed{a}+a}{\boxed{2}},\dfrac{\boxed{0}+b}{2}\right)=\left(\dfrac{\boxed{3}\boxed{a}}{\boxed{2}},\dfrac{\boxed{b}}{\boxed{2}}\right)

Length of MA:

MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=
\sqrt{\left(\dfrac{\boxed{3}a}{\boxed{2}}\right)^2+\left(\dfrac{b}{2}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}

Length of NB:

NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\
\sqrt{\left(\dfrac{-3a}{2}\right)^2+\left(\dfrac{b}{\boxed{2}}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}
5 0
3 years ago
Read 2 more answers
What two measurement could make up a complementary angle when one angle is 8 degrees more than the other?
Firdavs [7]
Complimentary angles add up to 90 degrees

x + y = 90
x = y + 8

y + 8 + y = 90
2y + 8 = 90
2y = 90 - 8
2y = 82
y = 82/2
y = 41

x = y + 8
x = 41 + 8
x = 49

so ur angles are : 41 and 49
7 0
3 years ago
Expand and simplify 2(x+7) + 3(x+1)
mash [69]

Let's simplify step-by-step.

2(x+7)+3(x+1)

Distribute:

=(2)(x)+(2)(7)+(3)(x)+(3)(1)

=2x+14+3x+3

Combine Like Terms:

=2x+14+3x+3

=(2x+3x)+(14+3)

=5x+17

your answer is 5x+17

8 0
3 years ago
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