All categories

2 years ago

Quadrilateral ABCD is inscribed in a circle What is the measure of angle A?

Mathematics

2 answers:

Contact [7]2 years ago

6 0

Answer:

77°

Step-by-step explanation:

ABCD is inscribed in a circle. Therefore it is a cyclic quadrilateral. Opposite angles of a cyclic quadrilateral are supplementary.

$\therefore \angle A + \angle C = 180° \\ (2x + 9) \degree + (3x + 1) \degree =180° \\ (5x + 10) \degree =180° \\ 5x + 10 = 180 \\ 5x = 180 - 10 \\ 5x = 170 \\ x = \frac{170}{5} \\ x = 34 \\ \angle A = (2 \times 34 + 9) \degree \\ \huge \red{ \boxed{\angle A= 77 \degree}} \\$

Katen [24]2 years ago

4 0

Answer:

Quadrilateral ABCD is inscribed in a circle, then

A + C = 180

=> 2x + 9 + 3x + 1 = 180

=> 5x = 170

=> x = 34

=> A = 2 x 34 + 9 = 77 deg

Hope this helps!

You might be interested in

A quarter is 1/4 dollar. Noah has 8 quarters. How much money does he have?

Dmitry_Shevchenko [17]

Answer:
noah has $2

step-by-step explanation:
1/4 * 8 = 8/4 = 2

4 0

2 years ago

-4 + 6g, for g = 4 i need in a sentence

laiz [17]

Answer:

-4+6*4 = 20

Step-by-step explanation:

If g is equal to 4 the answer is 20

8 0

3 years ago

Solve the equation. y +3=y+9

scoray [572]

Answer:

No solution

Step-by-step explanation:

=> y+3 = y+9

Subtracting both sides by y

=> $y+3-y = y+9-y$

=> 3 ≠ 9

So, This equation has no solution.

8 0

3 years ago

Is 5 1/2 yds greater than 192 ins?

iren2701 [21]

Answer:

Step-by-step explanation:

there is 12 inches in a foot

there are 3 feet in a yard

3 x 12 = 36 in in a yard

36 x 5 1/2 is 198

198 is greater than 192

6 0

3 years ago

Which two equations are true?(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)=6.6×10−10 (6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.

tiny-mole [99]

let me edit your question as:

Which two equations are true?

Eq1:

(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)

Eq2:

6.6×10−10(6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.7×103)

Eq3:

2.7×103(7.5×106)−(2.5×106)=5×100

Answer:

No one is true

Step-by-step explanation:

let's check each equation, if the values on both sides (left and right side) are equal then the equation is true otherwise false.

Using PEMDAS rule we are simplifying the equations as;

Eq1:

$(2*10-4)+(1.5*10-4)=3.5*10-4(3*10-5)+(2.2*10-5)\\(16)+(11)=35-4(25)+(17)\\27=35-100+17\\27=-48\\$

Eq2:

$6.6*10-10(6.3*10-1)-(2.1*10-1)=3*10-1(5.4*103)-(2.7*103)\\66-10(62)-(20)=30-1(556.2)-278.1\\66-620-20=30-556.2-278.1\\-574=-804.1$

Eq3:

$2.7*103(7.5*106)-(2.5*106)=5*100\\221089.5-265=500\\220824.5=500\\$

we observed that none of the equation has two same values on both sides thus none of the three equations is true.

Also, no value of Eq1, Eq2 or Eq3 are same thus none of the equation is true

8 0

3 years ago