Answer:
(A+B)(A+B)=A.A+B.A+A.B+B.B
Step-by-step explanation:
Given that matrices A and B are nxn matrices
We need to find (A+B)(A+B)
For understanding the multiplication of matrices let'take A is mxn and B is pxq matrices,we can multiple only when n=p,so our Ab matrices will be mxq.
We know that that in matrices AB is not equal to BA.
Now find
(A+B)(A+B)=A.A+B.A+A.B+B.B
So from we can say that (A+B)(A+B) is not equal to A.A+2B.A+B.B because AB is not equal to BA in matrices.
So (A+B)(A+B)=A.A+B.A+A.B+B.B
We write it out as an equation:
-1 = -2v + 2/3
Rearrange:
-1 -2/3 = -2v
Multiply by negative to equal positive
1 2/3 = 2v
Make 1 into a fraction
3/3 + 2/3 = 2v
5/3 = 2v
10/6 = 2v
5/6 = v
The answer is: v equals 5/6
Answer:
P(N = n) =
Step-by-step explanation:
to find out
Find the PMF PN (n)
solution
PN (n)
here N is random variable
and n is the number of times
so here N random variable is denote by the same package that is N (P)
so here
probability of N is
P(N ) = Ф ( N = n) .................. 1
here n is = 1, 2,3, 4,...................... and so on
so that here P(N = n) will be
P(N = n) =