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liberstina [14]
3 years ago
11

What is the solution of x^2+x-6/x-7<0 PLEASE HELP ME :( (it’s not the 2nd one i already tried it)

Mathematics
1 answer:
kupik [55]3 years ago
8 0
For x^2+x-6/x-7=0, I think it should be x=~2.59262 or x=~-2.75153 or x=~-0.84108
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A rectangle is 1/2 feet long and 3/4<br> feet wide.
Eddi Din [679]

Im not sure what you are asking is there another part to the question.

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3 years ago
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If a triangle has 3 side one is 12 one is 72 what is the last sude
harkovskaia [24]

this triangle has 3 sides one is 12, lets call this side a²

another side is 72, lets call this side c²

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to find the last side you do 72² - 12² = 5040

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We would like to create a confidence interval.
Vlada [557]

Answer:

c.A 90% confidence level and a sample size of 300 subjects.

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M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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In this problem

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So

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99% confidence interval

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The margin of error is

M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.3642\sqrt{\pi(1-\pi)}

b.A 90% confidence level and a sample size of 50 subjects.

n = 50

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So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The margin of error is

M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.2623\sqrt{\pi(1-\pi)}

c.A 90% confidence level and a sample size of 300 subjects.

n = 300

90% confidence interval

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The margin of error is

M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.0950\sqrt{\pi(1-\pi)}

This produces smallest margin of error.

d.A 99% confidence level and a sample size of 300 subjects.

n = 300

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So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The margin of error is

M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.1487\sqrt{\pi(1-\pi)}

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4 years ago
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san4es73 [151]

Answer:

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7 0
3 years ago
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