What type of number is -16.2i

Mathematics

2 answers:

azamat3 years ago

8 0

Answer:

Complex and imaginary number

Step-by-step explanation:

First, let's write the number $-16.2i$ in the form of $a+bi$ .

$0+ (-17)i$

Since $-16.2i$ can be written in the form of $a + bi$ , where $a$ and $b$ are real numbers, it is a complex number.

Also, since $a=0$ , it is also an imaginary number.

$-16.2i$ is complex and imaginary.

Gelneren [198K]3 years ago

3 0

Complex and imaginary number

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