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2 years ago

What type of number is -16.2i

Mathematics

2 answers:

azamat2 years ago

8 0

Answer:

Complex and imaginary number

Step-by-step explanation:

First, let's write the number $-16.2i$ in the form of $a+bi$ .

$0+ (-17)i$

Since $-16.2i$ can be written in the form of $a + bi$ , where $a$ and $b$ are real numbers, it is a complex number.

Also, since $a=0$ , it is also an imaginary number.

$-16.2i$ is complex and imaginary.

Gelneren [198K]2 years ago

3 0

Complex and imaginary number

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Equation for ( 6, 13) ( 7900, 5 )

tia_tia [17]

For this case we have that by definition, the equation of the line in the slope-intersection form is given by:

$y=mx+b$

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

We have the following points through which the line passes:

$(x_ {1}, y_ {1}) :( 6,13)\\(x_ {2}, y_ {2}): (7900,5)$

We find the slope of the line:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {5-13} {7900-6} = \frac {-8} {7894} = - \frac {4} {3947}$

Thus, the equation of the line is of the form:

$y = - \frac {4} {3947} x + b$

We substitute one of the points and find b:

$13 = - \frac {4} {3947} (6) + b\\13 = - \frac {24} {3947} + b\\13+ \frac {24} {3947} = b\\b = \frac {51335} {3947}$

Finally, the equation is:

$y = - \frac {4} {3947} x + \frac {51335} {3947}$

Answer:

$y = - \frac {4} {3947} x + \frac {51335} {3947}$

5 0

2 years ago

5(a-2b)-3(a-2b)<br><br>algebra2 .-.

d1i1m1o1n [39]

5(a - 2b) - 3(a - 2b) |use distributive property: a(b - c) = ab - ac

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7 0

2 years ago

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2 years ago

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Now we only care for the other 4 sets.

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1 year ago

I need help with this

Reil [10]

Answer:

see attached

Step-by-step explanation:

The domain is the horizontal extent of the graph. The graph extends to infinity in both directions horizontally (that's what the arrows mean). There are no "holes" because the open circle at x=-1 is matched by a filled circle at the same location.

The range is the vertical extent of the graph. The minimum is -3, which is included in the range. The maximum is infinity (as indicated by the up-pointing arrow).

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2 years ago