Answer:
-1, -1.1, 0.9, 1
Step-by-step explanation:
Answer:
16
Step-by-step explanation:
First you want to plug in all the numbers where the letters are
h ( j + i )- k(5) + h
3 ( 2 + 4 )- 1(5) + 3
After this step you will have to distribute the 3 outside the parenthesis. Which you do by multiplying everything in side the parenthesis by the outside number which is three.
6 + 12 - 1(5) + 3
Then you just follow PEMDAS to solve for the rest
6 + 12 - 5 + 3
18 - 5 + 3
13 + 3
16
Step-by-step explanation:
![\frac{y_2-y_1}{x_2-x_1}=\frac{15-(-13)}{28-(-28)}\\=\frac{28}{2(28)}\\\therefore\ m=\frac{1}{2}\\\frac{y-y_1}{xl-x_1}=m]\\\frac{y+13}{x+28}=\frac{1}{2}\\2y+26=x+28\\2y=x+2\\ y=\frac{1}{2}x+1](https://tex.z-dn.net/?f=%20%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%3D%5Cfrac%7B15-%28-13%29%7D%7B28-%28-28%29%7D%5C%5C%3D%5Cfrac%7B28%7D%7B2%2828%29%7D%5C%5C%5Ctherefore%5C%20m%3D%5Cfrac%7B1%7D%7B2%7D%5C%5C%5Cfrac%7By-y_1%7D%7Bxl-x_1%7D%3Dm%5D%5C%5C%5Cfrac%7By%2B13%7D%7Bx%2B28%7D%3D%5Cfrac%7B1%7D%7B2%7D%5C%5C2y%2B26%3Dx%2B28%5C%5C2y%3Dx%2B2%5C%5C%20y%3D%5Cfrac%7B1%7D%7B2%7Dx%2B1)
In order to find y for point C on AB, substitute point C in line equation if AB.

Answer:
Step-by-step explanation:
it becomes lighter :P or maybe you could say "bouncier" :P