I think the proportion of the numbers from 1-1000 that contains 3 is 261 out of 1000 number and it includes the numbers in 300 place. I hope you are satisfied with my answer and feel free to ask for more if you have clarifications and further questions.
I have no idea on D. Sorry. I hope this helps. They may not be right I didn’t quite understand the directions.
Answer:
The system of equations representing the situation are


with solutions


Step-by-step explanation:
Let us call
the number of associates and
the number of partners. If each associate costs $600 and each partner costs $1200, and it cost the law firm a total of $15,000, then we have
.
Since the law firm assigned at total of 16 lawyers, we have
.
Thus, the system of equations representing the situation are


And the solution to this system is found by solving for
in the second equation and substituting its value in the first equation:






We put this value into
and solve for 


Answer:
p = 4
Step-by-step explanation:
The usually recommended procedure for solving a proportion is to "cross multiply", then divide by the coefficient of the variable. (Solve the remaining one-step equation.)
<h3>Cross multiply</h3>
This means multiply both sides of the equation by the product of the denominators:
(15/6)(6p) = (10/p)(6p) . . . . "cross multiply"
15p = 60 . . . . . . simplify
<h3>Second step</h3>
Now, divide by the coefficient of the variable.
15p/15 = 60/15
p = 4
The solution is p = 4.
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<em>Additional comment</em>
If the variable is in the <em>numerator</em> of the proportion, using cross multiplication, you will find that you end up multiplying and dividing by the other denominator. To solve it in that case, you only need to multiply by the denominator under the variable.
__
For example, to solve ...
2/5 = p/10
you only need to multiply by 10. You don't need to multiply by 50, then divide by 5.
__
Any proportion can be written 4 ways:

This suggests another strategy: invert the whole proportion, then solve it as one with p in the numerator:
6/15 = p/10 ⇒ p = 10(6/15) = 4
Answer:
I could do 1 and 3
1) 2x-3y=-2 ....1
-
2x+y=14......2
=-4y=-16
y=4
<u>Substitute</u><u> </u><u>(</u><u>y</u><u>=</u><u>4</u><u>)</u><u> </u><u>into</u><u> </u><u>equation</u><u> </u><u>1</u>
2x-3 (4)=-2
2x-12=-2
2x=-2+12
2x=10
×=5
3) 5x+5y=20....1
-
-3x+5y=4......2
=8x=16
x=2
<u>S</u><u>ubstitute</u><u> </u><u>(</u><u>x</u><u>=</u><u>2</u><u>)</u><u> </u><u>into</u><u> </u><u>equation</u><u> </u><u>1</u>
<u>5</u><u> </u><u>(</u><u>2</u><u>)</u><u>+</u><u>5y</u><u>=</u><u>20</u>
<u>10</u><u>+</u><u>5y</u><u>=</u><u>20</u>
<u>5y</u><u>=</u><u>20-10</u>
<u>5y</u><u>=</u><u>10</u>
<u>y</u><u>=</u><u>2</u>