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maria [59]
3 years ago
8

Solve the inequality and graph the solution on the line provided. 7x - 17≤ 39

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
6 0
I’m pretty sure the answer to this is
X≤ 8
OleMash [197]3 years ago
5 0
X is less than or equal to 8
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Which fraction is greater,​2⁄3​or​1⁄3 ? How do you now?
m_a_m_a [10]
2/3 are greater and let’s say u have a pie and u cut it up in 3rds and u gave one piece to a friend and u keep the rest u will have more cause it closest to the whole and it just common knowledge
3 0
3 years ago
3. What are complementary events?
BARSIC [14]

Answer:

It's answer is C.

<u>They </u><u>are </u><u>two </u><u>events </u><u>in </u><u>which </u><u>either </u><u>one </u><u>or </u><u>the </u><u>other </u><u>must </u><u>happen</u><u>, </u><u> </u><u>but </u><u>they </u><u>cannot </u><u>happen </u><u>at </u><u>the </u><u>same </u><u>time</u><u>. </u>

8 0
3 years ago
Read 2 more answers
Can some one pls help me with this​
dmitriy555 [2]

Answer:

b

Step-by-step explanation:

jdkejwjdehfj

3 0
3 years ago
An ectopic pregnancy is twice as likely to develop when the pregnant woman is a smoker as it iswhen she is a nonsmoker. If 32 pe
Dmitriy789 [7]

Answer:

48.48%

Step-by-step explanation:

Let's assume that there is a number N of women.

32% of these are smokers, then there are 0.32*N smokers

then 68% of these are non-smokers, then there are 0.68*N non-smokers.

Let's assume that the probability of having a ectopic pregnancy for a non-smoker is p (and the probability for a smoker will be 2*p)

Then the number of women with an ectopic pregnancy that are non-smokers is:

p*0.68*N

The number of women with an ectopic pregnancy that are smokers is:

2*p*0.32*N

Then the total number of women with an ectopic pregnancy will be:

p*0.68*N + 2*p*0.32*N

The percentage of women having an ectopic pregnancy that are smokers is equal to the quotient between the number of women with an ectopic pregnancy that are smokers and the total number of women with an ectopic pregnancy, all that times 100%.

The percentage is:

P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\%

Taking p and N as common factors, we get:

P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\% = \frac{N*p}{N*p} \frac{2*0.32}{0.68 + 2*0.32} *100\%

Then we get:

\frac{2*0.32}{0.68 + 2*0.32} *100\% = 48.48\%

8 0
3 years ago
What does tanx sinx (cos^2x cscx- sinx) simplify to
Elan Coil [88]
Tanx sinx (cos^2x cscx- sinx)


=(sinx/cosx)((cos^2x cscx- sinx)

=(sinx/cosx)((cos^2x 1/sinx- sinx)

=(sinx/cosx)((cos^²x - sin²x)] / sinx

=(sinx/cosx)((cos^²x - sin²x)] / sinx

=(1/cosx)((cos^²x - sin²x)]

=(1/cosx)(2cos²x====> = 2 cos x]


7 0
4 years ago
Read 2 more answers
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